Timeline for On a Torus World and the force upon inhabitants
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Feb 28, 2022 at 0:55 | comment | added | Zoey | Thanks for the help. | |
| Feb 28, 2022 at 0:22 | comment | added | pb1729 | One other thing I should add is that in the artificially enclosed torus world, the Coriolis acceleration would be felt mainly by people jumping, or going up and down in elevators, since "radial" movement corresponds to up/down movement everywhere in that world. | |
| Feb 28, 2022 at 0:18 | comment | added | Zoey | I see what you were thinking, no, it isn't like that, sorry for not being clear. It is all basically the same distance to the axis of rotation. Though there would of course be small differences due to a completely perfect circle being basically impossible. | |
| Feb 28, 2022 at 0:14 | comment | added | pb1729 | Okay, cool, thanks for the additional detail, I was imagining something slightly different, where the torus has to be held together under its own gravity. Sounds like in your situation it's held together by the strength of the material. If the gravity from the torus itself isn't too strong, then that makes things much easier to analyze. Then the centrifugal force is the only source of gravity, and so you can just use the formula you already have. (And the force would be the same everywhere on the surface, since it's all the same distance from the axis of rotation.) | |
| Feb 28, 2022 at 0:10 | comment | added | Zoey | Will have to increase rotation period, as I don't want the Coriolis acceleration to be too extreme. Just gonna have to make it be more resource intensive. With a larger radius. | |
| Feb 28, 2022 at 0:07 | comment | added | Zoey | And on the exact situation, it is artificial, and atmosphere is artificially kept by a very strong glass overhang of sorts which surrounds it all. The surface is only the inside part, think you cut off the inner half of a torus, and have the surface be on the exposed inside. and thanks for the formulae. | |
| Feb 28, 2022 at 0:04 | comment | added | Zoey | The one I used was the one shown on Wikipedia, R = a(T/2pi)^2, with R being Radius in metres, a is the gravity in m/s2, and T is time in seconds. | |
| Feb 28, 2022 at 0:02 | history | answered | pb1729 | CC BY-SA 4.0 |