Timeline for Dimensions in lagrangian potential
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 7, 2013 at 11:12 | vote | accept | Raisa | ||
| Jul 7, 2013 at 11:11 | vote | accept | Raisa | ||
| Jul 7, 2013 at 11:12 | |||||
| Jul 7, 2013 at 11:11 | vote | accept | Raisa | ||
| Jul 7, 2013 at 11:11 | |||||
| Jul 7, 2013 at 5:48 | comment | added | Luboš Motl | @Vibert, I assure you that I wrote the same thing and at least minutes before you. ;-) | |
| Jul 1, 2013 at 12:01 | comment | added | Vibert | See my answer. The Langrangian density must have dimension $m^D = m^{d+1}.$ Derivatives have dimension $m^1$, so the dimension of $\phi$ follows from the fact that $(\partial \phi)^2 \sim m^{d+1}.$ | |
| Jul 1, 2013 at 10:32 | comment | added | Raisa | How $\phi$ has the dimension of $m^{d/2-1/2}$? | |
| Jul 1, 2013 at 8:27 | history | answered | Luboš Motl | CC BY-SA 3.0 |