Timeline for about laser wavelength and wave form
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 3, 2013 at 3:08 | comment | added | user1285419 | Thanks all. So does it mean the for monochromatic laser, the wave is harmonic with wavelength determined by the atomic resonance level of the media atom to generate laser? | |
| Jun 29, 2013 at 20:14 | comment | added | Groda.eu | If you think classically you can relate the frequency to the medium. In the harmonic approximation the system will behave like an electron bound to a positive core with a spring. Now Hooks law tells us that in that case the frequency increases as the square root of the force constant. In order for the electromagnetic field to interfere constructively with the electron it has to have the same frequency. So transitions involving strongly bound electrons will have higher frequencies, thus shorter wavelengths, than transitions involving weakly bound electrons. | |
| Jun 29, 2013 at 6:16 | comment | added | user6972 | @user1285419 I edited the answer to try to cover your questions. | |
| Jun 29, 2013 at 6:15 | history | edited | user6972 | CC BY-SA 3.0 |
added 1347 characters in body
|
| Jun 29, 2013 at 5:13 | comment | added | user1285419 | If that's the case, and if the laser propagates in the speed of light, so does it mean the wave is look $\sin(kx - kct)$ ? | |
| Jun 29, 2013 at 5:12 | comment | added | user1285419 | Thanks for your reply. It helps me to understand my question a lot. I still have two more questions. In 1), you said the wavelength is related to the medium, but is that any example to show how does it related? It is quite confusing because wavelength is the quantity about distance, I don't really understand how to control the wavelength of the output light (laser). And for the last question, as my understanding, do you mean along the wave propagation direction, the monochromatic laser like a sin wave but if we look at the cross section at any position, the intensity is Gaussian? | |
| Jun 29, 2013 at 4:40 | history | answered | user6972 | CC BY-SA 3.0 |