Timeline for Analytic solution to time-dependent Schrödinger equation
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Feb 21, 2022 at 14:29 | comment | added | NicAG | But the eigenvalues of the state are continuous here. So the sum is replaced by a momentum integral. But does $c(p)=\int \phi_p(x)\psi(x,0)dx$ still hold? | |
| Feb 19, 2022 at 8:40 | comment | added | Himanshu | @NicAG See the edit | |
| Feb 19, 2022 at 8:40 | history | edited | Himanshu | CC BY-SA 4.0 |
doubt on comment is resolved now.
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| Feb 18, 2022 at 18:17 | comment | added | NicAG | Above $g$ is $F$. | |
| Feb 18, 2022 at 18:07 | comment | added | NicAG | $\phi(p)=C \cdot exp[-i/F(Ep-\frac{p^3}{2m})+i(\frac{p^2}{2m}+Fx)t]=C \cdot exp[-i/F(\frac{-2p^3}{3m}+gxp)+i(\frac{p^2}{2m}+Fx)t]$ $\phi(x,t)=\int dp^3 \phi(p,t)e^{ipx}$ is my solution. But how do I implement the initial condition, i.e. $\phi(x,0)$. | |
| Feb 18, 2022 at 15:57 | comment | added | Mauricio | You should clarify what happens with the time dependence. | |
| Feb 18, 2022 at 12:26 | history | edited | Ruslan | CC BY-SA 4.0 |
added 11 characters in body
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| Feb 18, 2022 at 4:02 | history | answered | Himanshu | CC BY-SA 4.0 |