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Oct 9, 2022 at 23:57 answer added Joe timeline score: 0
Feb 16, 2022 at 19:07 history edited Qmechanic CC BY-SA 4.0
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Feb 16, 2022 at 17:28 vote accept a9302c
Feb 16, 2022 at 17:04 answer added Dale timeline score: 2
Feb 16, 2022 at 17:03 comment added J.G. To solve $\dot{v}=-kv^2$ with $1$-dimensional $v$, restate that as $\frac{dt}{dv}=-\frac{1}{kv^2}$.
S Feb 16, 2022 at 16:50 review First questions
Feb 16, 2022 at 17:12
S Feb 16, 2022 at 16:50 history asked a9302c CC BY-SA 4.0