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Feb 6, 2022 at 19:30 vote accept awsomeguy
Feb 4, 2022 at 15:09 answer added octonion timeline score: 1
Feb 4, 2022 at 14:27 comment added Prahar $D$ is a representation of the Lorentz group. You can use this to build a representation of the Poincare group by taking a field at the origin $x=0$ and then defining its Lorentz representation at that point. Then you use the translation generators to translate it to a generic point $x$. Following this construction it is clear that the $x$ dependence of $D$ would be completely fixed by symmetry arguments. The fact that it is independent of $x$ is a consequence of the calculation.
Feb 4, 2022 at 14:13 history edited Qmechanic CC BY-SA 4.0
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Feb 4, 2022 at 14:09 history asked awsomeguy CC BY-SA 4.0