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The mass properties of an object are found using a volume integralvolume integral.

The general procedure is a mathematical summation of the volume of the solid. There are several steps needed to be taken to get the final result and they are outlined below: (caution, calculus ahead)

  1. Volume - The solid is parametrized in a way the volume can be summed by $$V = \int {\rm d}V$$

    • There are various common ${\rm d}V$ expressions depending on the geometry, such as ${\rm d}V = {\rm d}x\, {\rm d}y\, {\rm d z}$ or ${\rm d}V = r\,{\rm d}r\,{\rm d}\theta\,{\rm d}z$.

      There are various common ${\rm d}V$ expressions depending on the geometry, such as ${\rm d}V = {\rm d}x\, {\rm d}y\, {\rm d z}$ or ${\rm d}V = r\,{\rm d}r\,{\rm d}\theta\,{\rm d}z$.
    • For the most general case if the interior points of the solid can be expressed in terms of a vector with three parameters $\vec{\rm pos}(u,v,w)$ then the volume differential is $${\rm d}V = \left| \frac{\partial \vec{\rm pos}}{\partial u} \cdot (\frac{\partial \vec{\rm pos}}{\partial v} \times \frac{\partial \vec{\rm pos}}{\partial w}) \right| {\rm d}u\,{\rm d}v\,{\rm d}w$$

      Here $\cdot$ is the vector inner product, and $\times$ the vector cross product.

      For the most general case if the interior points of the solid can be expressed in terms of a vector with three parameters $\vec{\rm pos}(u,v,w)$ then the volume differential is $${\rm d}V = \left| \frac{\partial \vec{\rm pos}}{\partial u} \cdot (\frac{\partial \vec{\rm pos}}{\partial v} \times \frac{\partial \vec{\rm pos}}{\partial w}) \right| {\rm d}u\,{\rm d}v\,{\rm d}w$$ Here $\cdot$ is the vector inner product, and $\times$ the vector cross product.
    • Volume Element in Wikipedia has more details on how ${\rm d}V$ is defined for solids.
  2. Mass - The volume integral is summed over the density function $$ m = \int \rho\,{\rm d}V$$ If density is assumed to be constant, then the above is usually flipped to set $\rho = m/V$ in the equations below.

  3. Center of Mass - The volume integral is summed over the position function $$ \vec{\rm com} = \frac{1}{m} \int (\vec{\rm pos})\,\rho {\rm d}V$$

  4. Mass moment of inertia (tensor) about origin - The MMOI of the body about the origin is evaluated with the volume integral summing the MMOI of each particle in the solid $$ \mathrm{I}_O = \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \, \rho\,{\rm d}V$$ Here $\cdot$ is the vector inner product, and $\otimes$ the vector outer product.

    an alternate form of the above is $$ \mathrm{I}_O = \int \begin{vmatrix} z^2+y^2 & -x y & -x z \\ -x y & x^2+z^2 & - y z \\ -x z & -y z & x^2+y^2 \end{vmatrix} \, \rho\,{\rm d}V$$

    for the case with uniform density, usually, MMOI is expressed in terms of a known mass, which is done by taking the density out of the integral $$ \mathrm{I}_O = \frac{m}{V} \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \,{\rm d}V$$

  5. Mass moment of inertia (tensor) about the center of mass - Finally the parallel axis theorem must be applied to transform the MMOI about the origin $\mathrm{I}_O$ to the MMOI about the center of mass $\mathrm{I}_C$ $$\mathrm{I}_C = \mathrm{I}_O - m ( \vec{\rm com} \cdot \vec{\rm com} - \vec{\rm com} \otimes \vec{\rm com})$$

The above describes MMOI in the most general approach possible, in order to be able to apply it to various scenarios.

The mass properties of an object are found using a volume integral.

The general procedure is a mathematical summation of the volume of the solid. There are several steps needed to be taken to get the final result and they are outlined below: (caution, calculus ahead)

  1. Volume - The solid is parametrized in a way the volume can be summed by $$V = \int {\rm d}V$$

    • There are various common ${\rm d}V$ expressions depending on the geometry, such as ${\rm d}V = {\rm d}x\, {\rm d}y\, {\rm d z}$ or ${\rm d}V = r\,{\rm d}r\,{\rm d}\theta\,{\rm d}z$.

    • For the most general case if the interior points of the solid can be expressed in terms of a vector with three parameters $\vec{\rm pos}(u,v,w)$ then the volume differential is $${\rm d}V = \left| \frac{\partial \vec{\rm pos}}{\partial u} \cdot (\frac{\partial \vec{\rm pos}}{\partial v} \times \frac{\partial \vec{\rm pos}}{\partial w}) \right| {\rm d}u\,{\rm d}v\,{\rm d}w$$

      Here $\cdot$ is the vector inner product, and $\times$ the vector cross product.

  2. Mass - The volume integral is summed over the density function $$ m = \int \rho\,{\rm d}V$$ If density is assumed to be constant, then the above is usually flipped to set $\rho = m/V$ in the equations below.

  3. Center of Mass - The volume integral is summed over the position function $$ \vec{\rm com} = \frac{1}{m} \int (\vec{\rm pos})\,\rho {\rm d}V$$

  4. Mass moment of inertia (tensor) about origin - The MMOI of the body about the origin is evaluated with the volume integral summing the MMOI of each particle in the solid $$ \mathrm{I}_O = \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \, \rho\,{\rm d}V$$ Here $\cdot$ is the vector inner product, and $\otimes$ the vector outer product.

    an alternate form of the above is $$ \mathrm{I}_O = \int \begin{vmatrix} z^2+y^2 & -x y & -x z \\ -x y & x^2+z^2 & - y z \\ -x z & -y z & x^2+y^2 \end{vmatrix} \, \rho\,{\rm d}V$$

    for the case with uniform density, usually, MMOI is expressed in terms of a known mass, which is done by taking the density out of the integral $$ \mathrm{I}_O = \frac{m}{V} \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \,{\rm d}V$$

  5. Mass moment of inertia (tensor) about the center of mass - Finally the parallel axis theorem must be applied to transform the MMOI about the origin $\mathrm{I}_O$ to the MMOI about the center of mass $\mathrm{I}_C$ $$\mathrm{I}_C = \mathrm{I}_O - m ( \vec{\rm com} \cdot \vec{\rm com} - \vec{\rm com} \otimes \vec{\rm com})$$

The above describes MMOI in the most general approach possible, in order to be able to apply it to various scenarios.

The mass properties of an object are found using a volume integral.

The general procedure is a mathematical summation of the volume of the solid. There are several steps needed to be taken to get the final result and they are outlined below: (caution, calculus ahead)

  1. Volume - The solid is parametrized in a way the volume can be summed by $$V = \int {\rm d}V$$

    • There are various common ${\rm d}V$ expressions depending on the geometry, such as ${\rm d}V = {\rm d}x\, {\rm d}y\, {\rm d z}$ or ${\rm d}V = r\,{\rm d}r\,{\rm d}\theta\,{\rm d}z$.
    • For the most general case if the interior points of the solid can be expressed in terms of a vector with three parameters $\vec{\rm pos}(u,v,w)$ then the volume differential is $${\rm d}V = \left| \frac{\partial \vec{\rm pos}}{\partial u} \cdot (\frac{\partial \vec{\rm pos}}{\partial v} \times \frac{\partial \vec{\rm pos}}{\partial w}) \right| {\rm d}u\,{\rm d}v\,{\rm d}w$$ Here $\cdot$ is the vector inner product, and $\times$ the vector cross product.
    • Volume Element in Wikipedia has more details on how ${\rm d}V$ is defined for solids.
  2. Mass - The volume integral is summed over the density function $$ m = \int \rho\,{\rm d}V$$ If density is assumed to be constant, then the above is usually flipped to set $\rho = m/V$ in the equations below.

  3. Center of Mass - The volume integral is summed over the position function $$ \vec{\rm com} = \frac{1}{m} \int (\vec{\rm pos})\,\rho {\rm d}V$$

  4. Mass moment of inertia (tensor) about origin - The MMOI of the body about the origin is evaluated with the volume integral summing the MMOI of each particle in the solid $$ \mathrm{I}_O = \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \, \rho\,{\rm d}V$$ Here $\cdot$ is the vector inner product, and $\otimes$ the vector outer product.

    an alternate form of the above is $$ \mathrm{I}_O = \int \begin{vmatrix} z^2+y^2 & -x y & -x z \\ -x y & x^2+z^2 & - y z \\ -x z & -y z & x^2+y^2 \end{vmatrix} \, \rho\,{\rm d}V$$

    for the case with uniform density, usually, MMOI is expressed in terms of a known mass, which is done by taking the density out of the integral $$ \mathrm{I}_O = \frac{m}{V} \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \,{\rm d}V$$

  5. Mass moment of inertia (tensor) about the center of mass - Finally the parallel axis theorem must be applied to transform the MMOI about the origin $\mathrm{I}_O$ to the MMOI about the center of mass $\mathrm{I}_C$ $$\mathrm{I}_C = \mathrm{I}_O - m ( \vec{\rm com} \cdot \vec{\rm com} - \vec{\rm com} \otimes \vec{\rm com})$$

The above describes MMOI in the most general approach possible, in order to be able to apply it to various scenarios.

added 335 characters in body
Source Link
John Alexiou
  • 39.3k
  • 6
  • 72
  • 182

The mass properties of an object are found using a volume integral.

The general procedure is as followsa mathematical summation of the volume of the solid. There are several steps needed to be taken to get the final result and they are outlined below: (caution, calculus ahead)

  1. Volume - The solid is parametrized in a way the volume can be summed by $$V = \int {\rm d}V$$

    • There are various common ${\rm d}V$ expressions depending on the geometry, such as ${\rm d}V = {\rm d}x\, {\rm d}y\, {\rm d z}$ or ${\rm d}V = r\,{\rm d}r\,{\rm d}\theta\,{\rm d}z$.

    • For the most general case if the interior points of the solid can be expressed in terms of a vector with three parameters $\vec{\rm pos}(u,v,w)$ then the volume differential is $${\rm d}V = \left| \frac{\partial \vec{\rm pos}}{\partial u} \cdot (\frac{\partial \vec{\rm pos}}{\partial v} \times \frac{\partial \vec{\rm pos}}{\partial w}) \right| {\rm d}u\,{\rm d}v\,{\rm d}w$$

      Here $\cdot$ is the vector inner product, and $\times$ the vector cross product.

  2. Mass - The volume integral is summed over the density function $$ m = \int \rho\,{\rm d}V$$ If density is assumed to be constant, then the above is usually flipped to set $\rho = m/V$ in the equations below.

  3. Center of Mass - The volume integral is summed over the position function $$ \vec{\rm com} = \frac{1}{m} \int (\vec{\rm pos})\,\rho {\rm d}V$$

  4. Mass moment of inertia (tensor) about origin - The MMOI of the body about the origin is evaluated with the volume integral summing the MMOI of each particle in the solid $$ \mathrm{I}_O = \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \, \rho\,{\rm d}V$$ Here $\cdot$ is the vector inner product, and $\otimes$ the vector outer product.

    an alternate form of the above is $$ \mathrm{I}_O = \int \begin{vmatrix} z^2+y^2 & -x y & -x z \\ -x y & x^2+z^2 & - y z \\ -x z & -y z & x^2+y^2 \end{vmatrix} \, \rho\,{\rm d}V$$

    for the case with uniform density, usually, MMOI is expressed in terms of a known mass, which is done by taking the density out of the integral $$ \mathrm{I}_O = \frac{m}{V} \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \,{\rm d}V$$

  5. Mass moment of inertia (tensor) about the center of mass - Finally the parallel axis theorem must be applied to transform the MMOI about the origin $\mathrm{I}_O$ to the MMOI about the center of mass $\mathrm{I}_C$ $$\mathrm{I}_C = \mathrm{I}_O - m ( \vec{\rm com} \cdot \vec{\rm com} - \vec{\rm com} \otimes \vec{\rm com})$$

The above describes MMOI in the most general approach possible, in order to be able to apply it to various scenarios.

The mass properties of an object are found using a volume integral.

The general procedure is as follows

  1. Volume - The solid is parametrized in a way the volume can be summed by $$V = \int {\rm d}V$$

    • There are various common ${\rm d}V$ expressions depending on the geometry, such as ${\rm d}V = {\rm d}x\, {\rm d}y\, {\rm d z}$ or ${\rm d}V = r\,{\rm d}r\,{\rm d}\theta\,{\rm d}z$.

    • For the most general case if the interior points of the solid can be expressed in terms of a vector with three parameters $\vec{\rm pos}(u,v,w)$ then the volume differential is $${\rm d}V = \left| \frac{\partial \vec{\rm pos}}{\partial u} \cdot (\frac{\partial \vec{\rm pos}}{\partial v} \times \frac{\partial \vec{\rm pos}}{\partial w}) \right| {\rm d}u\,{\rm d}v\,{\rm d}w$$

      Here $\cdot$ is the vector inner product, and $\times$ the vector cross product.

  2. Mass - The volume integral is summed over the density function $$ m = \int \rho\,{\rm d}V$$ If density is assumed to be constant, then the above is usually flipped to set $\rho = m/V$ in the equations below.

  3. Center of Mass - The volume integral is summed over the position function $$ \vec{\rm com} = \frac{1}{m} \int (\vec{\rm pos})\,\rho {\rm d}V$$

  4. Mass moment of inertia (tensor) about origin - The MMOI of the body about the origin is evaluated with the volume integral summing the MMOI of each particle in the solid $$ \mathrm{I}_O = \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \, \rho\,{\rm d}V$$ Here $\cdot$ is the vector inner product, and $\otimes$ the vector outer product.

    an alternate form of the above is $$ \mathrm{I}_O = \int \begin{vmatrix} z^2+y^2 & -x y & -x z \\ -x y & x^2+z^2 & - y z \\ -x z & -y z & x^2+y^2 \end{vmatrix} \, \rho\,{\rm d}V$$

    for the case with uniform density, usually, MMOI is expressed in terms of a known mass, which is done by taking the density out of the integral $$ \mathrm{I}_O = \frac{m}{V} \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \,{\rm d}V$$

  5. Mass moment of inertia (tensor) about the center of mass - Finally the parallel axis theorem must be applied to transform the MMOI about the origin $\mathrm{I}_O$ to the MMOI about the center of mass $\mathrm{I}_C$ $$\mathrm{I}_C = \mathrm{I}_O - m ( \vec{\rm com} \cdot \vec{\rm com} - \vec{\rm com} \otimes \vec{\rm com})$$

The above describes MMOI in the most general approach possible, in order to be able to apply it to various scenarios.

The mass properties of an object are found using a volume integral.

The general procedure is a mathematical summation of the volume of the solid. There are several steps needed to be taken to get the final result and they are outlined below: (caution, calculus ahead)

  1. Volume - The solid is parametrized in a way the volume can be summed by $$V = \int {\rm d}V$$

    • There are various common ${\rm d}V$ expressions depending on the geometry, such as ${\rm d}V = {\rm d}x\, {\rm d}y\, {\rm d z}$ or ${\rm d}V = r\,{\rm d}r\,{\rm d}\theta\,{\rm d}z$.

    • For the most general case if the interior points of the solid can be expressed in terms of a vector with three parameters $\vec{\rm pos}(u,v,w)$ then the volume differential is $${\rm d}V = \left| \frac{\partial \vec{\rm pos}}{\partial u} \cdot (\frac{\partial \vec{\rm pos}}{\partial v} \times \frac{\partial \vec{\rm pos}}{\partial w}) \right| {\rm d}u\,{\rm d}v\,{\rm d}w$$

      Here $\cdot$ is the vector inner product, and $\times$ the vector cross product.

  2. Mass - The volume integral is summed over the density function $$ m = \int \rho\,{\rm d}V$$ If density is assumed to be constant, then the above is usually flipped to set $\rho = m/V$ in the equations below.

  3. Center of Mass - The volume integral is summed over the position function $$ \vec{\rm com} = \frac{1}{m} \int (\vec{\rm pos})\,\rho {\rm d}V$$

  4. Mass moment of inertia (tensor) about origin - The MMOI of the body about the origin is evaluated with the volume integral summing the MMOI of each particle in the solid $$ \mathrm{I}_O = \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \, \rho\,{\rm d}V$$ Here $\cdot$ is the vector inner product, and $\otimes$ the vector outer product.

    an alternate form of the above is $$ \mathrm{I}_O = \int \begin{vmatrix} z^2+y^2 & -x y & -x z \\ -x y & x^2+z^2 & - y z \\ -x z & -y z & x^2+y^2 \end{vmatrix} \, \rho\,{\rm d}V$$

    for the case with uniform density, usually, MMOI is expressed in terms of a known mass, which is done by taking the density out of the integral $$ \mathrm{I}_O = \frac{m}{V} \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \,{\rm d}V$$

  5. Mass moment of inertia (tensor) about the center of mass - Finally the parallel axis theorem must be applied to transform the MMOI about the origin $\mathrm{I}_O$ to the MMOI about the center of mass $\mathrm{I}_C$ $$\mathrm{I}_C = \mathrm{I}_O - m ( \vec{\rm com} \cdot \vec{\rm com} - \vec{\rm com} \otimes \vec{\rm com})$$

The above describes MMOI in the most general approach possible, in order to be able to apply it to various scenarios.

added 335 characters in body
Source Link
John Alexiou
  • 39.3k
  • 6
  • 72
  • 182

The mass properties of an object are found using a volume integral.

The general procedure is as follows

  1. Volume - The solid is parametrized in a way the volume can be summed by $$V = \int {\rm d}V$$

    • There are various common ${\rm d}V$ expressions depending on the geometry, such as ${\rm d}V = {\rm d}x\, {\rm d}y\, {\rm d z}$ or ${\rm d}V = r\,{\rm d}r\,{\rm d}\theta\,{\rm d}z$.

    • For the most general case if the interior points of the solid can be expressed in terms of a vector with three parameters $\vec{\rm pos}(u,v,w)$ then the volume differential is $${\rm d}V = \left| \frac{\partial \vec{\rm pos}}{\partial u} \cdot (\frac{\partial \vec{\rm pos}}{\partial v} \times \frac{\partial \vec{\rm pos}}{\partial w}) \right| {\rm d}u\,{\rm d}v\,{\rm d}w$$

      Here $\cdot$ is the vector inner product, and $\times$ the vector cross product.

  2. Mass - The volume integral is summed over the density function $$ m = \int \rho\,{\rm d}V$$ If density is assumed to be constant, then the above is usually flipped to set $\rho = m/V$ in the equations below.

  3. Center of Mass - The volume integral is summed over the position function $$ \vec{\rm com} = \frac{1}{m} \int (\vec{\rm pos})\,\rho {\rm d}V$$

  4. Mass moment of inertia (tensor) about origin - The MMOI of the body about the origin is evaluated with the volume integral summing the MMOI of each particle in the solid $$ \mathrm{I}_O = \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \, \rho\,{\rm d}V$$ Here $\cdot$ is the vector inner product, and $\otimes$ the vector outer product.

    an alternate form of the above is $$ \mathrm{I}_O = \int \begin{vmatrix} z^2+y^2 & -x y & -x z \\ -x y & x^2+z^2 & - y z \\ -x z & -y z & x^2+y^2 \end{vmatrix} \, \rho\,{\rm d}V$$

    for the case with uniform density, usually, MMOI is expressed in terms of a known mass, which is done by taking the density out of the integral $$ \mathrm{I}_O = \frac{m}{V} \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \,{\rm d}V$$

  5. Mass moment of inertia (tensor) about the center of mass - Finally the parallel axis theorem must be applied to transform the MMOI about the origin $\mathrm{I}_O$ to the MMOI about the center of mass $\mathrm{I}_C$ $$\mathrm{I}_C = \mathrm{I}_O - m ( \vec{\rm com} \cdot \vec{\rm com} - \vec{\rm com} \otimes \vec{\rm com})$$

The above describes MMOI in the most general approach possible, in order to be able to apply it to various scenarios.

The mass properties of an object are found using a volume integral.

The general procedure is as follows

  1. Volume - The solid is parametrized in a way the volume can be summed by $$V = \int {\rm d}V$$

    • There are various common ${\rm d}V$ expressions depending on the geometry, such as ${\rm d}V = {\rm d}x\, {\rm d}y\, {\rm d z}$ or ${\rm d}V = r\,{\rm d}r\,{\rm d}\theta\,{\rm d}z$.

    • For the most general case if the interior points of the solid can be expressed in terms of a vector with three parameters $\vec{\rm pos}(u,v,w)$ then the volume differential is $${\rm d}V = \left| \frac{\partial \vec{\rm pos}}{\partial u} \cdot (\frac{\partial \vec{\rm pos}}{\partial v} \times \frac{\partial \vec{\rm pos}}{\partial w}) \right| {\rm d}u\,{\rm d}v\,{\rm d}w$$

      Here $\cdot$ is the vector inner product, and $\times$ the vector cross product.

  2. Mass - The volume integral is summed over the density function $$ m = \int \rho\,{\rm d}V$$

  3. Center of Mass - The volume integral is summed over the position function $$ \vec{\rm com} = \frac{1}{m} \int (\vec{\rm pos})\,\rho {\rm d}V$$

  4. Mass moment of inertia (tensor) about origin - The MMOI of the body about the origin is evaluated with the volume integral summing the MMOI of each particle in the solid $$ \mathrm{I}_O = \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \, \rho\,{\rm d}V$$ Here $\cdot$ is the vector inner product, and $\otimes$ the vector outer product.

    an alternate form of the above is $$ \mathrm{I}_O = \int \begin{vmatrix} z^2+y^2 & -x y & -x z \\ -x y & x^2+z^2 & - y z \\ -x z & -y z & x^2+y^2 \end{vmatrix} \, \rho\,{\rm d}V$$

  5. Mass moment of inertia (tensor) about the center of mass - Finally the parallel axis theorem must be applied to transform the MMOI about the origin $\mathrm{I}_O$ to the MMOI about the center of mass $\mathrm{I}_C$ $$\mathrm{I}_C = \mathrm{I}_O - m ( \vec{\rm com} \cdot \vec{\rm com} - \vec{\rm com} \otimes \vec{\rm com})$$

The above describes MMOI in the most general approach possible, in order to be able to apply it to various scenarios.

The mass properties of an object are found using a volume integral.

The general procedure is as follows

  1. Volume - The solid is parametrized in a way the volume can be summed by $$V = \int {\rm d}V$$

    • There are various common ${\rm d}V$ expressions depending on the geometry, such as ${\rm d}V = {\rm d}x\, {\rm d}y\, {\rm d z}$ or ${\rm d}V = r\,{\rm d}r\,{\rm d}\theta\,{\rm d}z$.

    • For the most general case if the interior points of the solid can be expressed in terms of a vector with three parameters $\vec{\rm pos}(u,v,w)$ then the volume differential is $${\rm d}V = \left| \frac{\partial \vec{\rm pos}}{\partial u} \cdot (\frac{\partial \vec{\rm pos}}{\partial v} \times \frac{\partial \vec{\rm pos}}{\partial w}) \right| {\rm d}u\,{\rm d}v\,{\rm d}w$$

      Here $\cdot$ is the vector inner product, and $\times$ the vector cross product.

  2. Mass - The volume integral is summed over the density function $$ m = \int \rho\,{\rm d}V$$ If density is assumed to be constant, then the above is usually flipped to set $\rho = m/V$ in the equations below.

  3. Center of Mass - The volume integral is summed over the position function $$ \vec{\rm com} = \frac{1}{m} \int (\vec{\rm pos})\,\rho {\rm d}V$$

  4. Mass moment of inertia (tensor) about origin - The MMOI of the body about the origin is evaluated with the volume integral summing the MMOI of each particle in the solid $$ \mathrm{I}_O = \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \, \rho\,{\rm d}V$$ Here $\cdot$ is the vector inner product, and $\otimes$ the vector outer product.

    an alternate form of the above is $$ \mathrm{I}_O = \int \begin{vmatrix} z^2+y^2 & -x y & -x z \\ -x y & x^2+z^2 & - y z \\ -x z & -y z & x^2+y^2 \end{vmatrix} \, \rho\,{\rm d}V$$

    for the case with uniform density, usually, MMOI is expressed in terms of a known mass, which is done by taking the density out of the integral $$ \mathrm{I}_O = \frac{m}{V} \int ( \vec{\rm pos} \cdot \vec{\rm pos} - \vec{\rm pos} \otimes \vec{\rm pos}) \,{\rm d}V$$

  5. Mass moment of inertia (tensor) about the center of mass - Finally the parallel axis theorem must be applied to transform the MMOI about the origin $\mathrm{I}_O$ to the MMOI about the center of mass $\mathrm{I}_C$ $$\mathrm{I}_C = \mathrm{I}_O - m ( \vec{\rm com} \cdot \vec{\rm com} - \vec{\rm com} \otimes \vec{\rm com})$$

The above describes MMOI in the most general approach possible, in order to be able to apply it to various scenarios.

added 335 characters in body
Source Link
John Alexiou
  • 39.3k
  • 6
  • 72
  • 182
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Source Link
John Alexiou
  • 39.3k
  • 6
  • 72
  • 182
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