Timeline for Why isn't a pseudo force considered for a block on an accelerating block?
Current License: CC BY-SA 4.0
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Jun 28 at 4:43 | answer | added | RC_23 | timeline score: 0 | |
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Jan 25, 2022 at 21:29 | comment | added | Bob D | I don’t agree with their first statement of the solution in the link provided. It says: “If no force is applied, the block A will slip on block C and block B will move downwards”. That will only be the case if the coefficient of static friction is less than 1, which they did not indicate. The block will not slide if $\mu\ge1$. To me that makes the rest of their solution suspect. | |
Jan 25, 2022 at 21:06 | comment | added | Bob D | I looked at their solution and believe it incorrect at the start. | |
Jan 25, 2022 at 9:40 | comment | added | Bob D | The only problem with my approach is the min and max forces may entail two different value of u. I’ll have to work it out | |
Jan 25, 2022 at 9:37 | comment | added | Bob D | Also, without looking at the solution, I would think the maximum force would be when the tension is zero because then the only force accelerating A would be the static friction force exerted forward by C. | |
Jan 25, 2022 at 9:07 | comment | added | Bob D | Without even looking at the solution if u>1 and F=0 the blocks would be in equilibrium | |
Jan 25, 2022 at 8:22 | comment | added | udbhavs | Thanks, the example asks for both the minimum and maximum forces which I assume is accounting for friction in both directions. Here is the solved example from the book. It does look like the value of $a$ used in it for the system and for block A is the same. | |
Jan 24, 2022 at 22:20 | comment | added | Bob D | IMO your next to last paragraph reveals the dilemma of this problem. Which direction do we choose for the static friction force that C exerts on A? Clearly when $F=0$ (block C at rest), it acts to the left to oppose $T$. (But it is not $\mu mg$ unless $T$ equals the maximum possible static friction force). But once C begins to accelerates to the right the tension will drop due to the static friction that develops between B and C acting upward and so will the magnitude of the static friction on A that opposes T. I'm working on some free body diagrams to attempt to resolve. | |
Jan 24, 2022 at 9:39 | answer | added | gandalf61 | timeline score: 0 | |
Jan 24, 2022 at 9:30 | history | edited | Qmechanic♦ |
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S Jan 24, 2022 at 9:26 | review | First questions | |||
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S Jan 24, 2022 at 9:26 | history | asked | udbhavs | CC BY-SA 4.0 |