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Post Closed as "Not suitable for this site" by Farcher, Dale, jng224, Voulkos, Bob D
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Qmechanic
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Apply superposition principle to compute current in the 2-Ω$2Ω$ resistor shown in the figure  . All resistors are in ohms

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Apply superposition principle to compute current in the 2-Ω resistor shown in the figure . All resistors are in ohms

So in this question what I tried to do was first remove the 6A source and then try to apply the current divider rule according to which the current I = 24 x (4/12) = 8A and then remove the 24A source and then again try to apply the current divider rule according to which the current i = 6 x (6/12) = 3A and the final answer I arrived at was I(total) = I-i(cause 3A is in opposite direction) = 5A. Is it the correct way to apply the current divider rule in this question?

Ignore the blue dash in the question.

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