Timeline for Can dark energy dominate from the Big-Bang?
Current License: CC BY-SA 4.0
11 events
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| Jan 7, 2022 at 16:32 | comment | added | Buzz | By the way, the integral has a solution when one chooses the constant C = 0, That is, a=0, and the integral is also 0. | |
| Jan 7, 2022 at 16:32 | comment | added | ohneVal | That is exactly what I explain in my answer | |
| Jan 7, 2022 at 16:23 | comment | added | Buzz | Here is another way to look at this. da/a = Ho dt has the solution a =C e^(Ho t), where C is the constant of integration.. Therefore, when t=0, a = C. When t=T, a = C e^(Ho T). Since a cannot be zero, the limits on the integral of da/a cannot be 0 to 1. The limits will be C to C e^(Ho T). This means you cannot integrate da/a from zero. Also, there is only space that expands, but nothing in space to move apart. | |
| Jan 7, 2022 at 15:52 | comment | added | Buzz | I suggest you analyze the equation in which 0<ΩNR<<1, and ΩΛ=1-ΩNR. Then explore what happens as ΩNR approaches zero. | |
| Jan 7, 2022 at 15:47 | comment | added | ohneVal | There is, that is the whole point of a cosmological constant, it corresponds to negative pressure. Solve the differential equation as you can see. Alternatively have a look at de Sitter space. | |
| Jan 7, 2022 at 15:42 | comment | added | Buzz | What is your source for concluding that there is NOT no expansion because there is nothing in this universe model to expand? | |
| Jan 7, 2022 at 9:37 | comment | added | ohneVal | As long as there is a cosmological constant there will be expansion and $a$ is cannot be constant. | |
| Jan 6, 2022 at 0:06 | history | edited | Buzz | CC BY-SA 4.0 |
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| Jan 5, 2022 at 23:56 | history | edited | Buzz | CC BY-SA 4.0 |
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| Jan 5, 2022 at 23:47 | history | edited | Buzz | CC BY-SA 4.0 |
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| Jan 5, 2022 at 16:20 | history | answered | Buzz | CC BY-SA 4.0 |