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Dec 4, 2021 at 0:27 vote accept tomdodd4598
Dec 4, 2021 at 0:17 comment added tomdodd4598 Ah, I see now, thanks... $e^{i 2 \pi n}$ is only $1$ for integral $n$, and so the definition of a representation only holds for integral $n$. Very interesting! Right, I think I have one more question to post on this topic before I can feel better about it :P
Dec 4, 2021 at 0:09 history edited ACuriousMind CC BY-SA 4.0
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Dec 4, 2021 at 0:06 comment added ACuriousMind @turbodiesel4598 I wrote down an equation that must hold for $\rho_n$ to be a group homomorphism (that I actually had a typo in, corrected now). What happens for non-integral $n$? (Further hint: The l.h.s. is $\rho_n(\mathrm{e}^{\mathrm{i}2\pi}) = \rho_n(1) = 1$)
Dec 3, 2021 at 23:59 comment added tomdodd4598 I suppose the problem is that I don't see what goes wrong for non-integral $n$. It might be something subtle or just because I don't know enough group/representation theory.
Dec 3, 2021 at 22:42 history answered ACuriousMind CC BY-SA 4.0