Timeline for College Board Problem: Conservation of Momentum -> Conservation of Energy in a Spring
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 6, 2021 at 17:26 | comment | added | R.W. Bird | I agree with your h = .145 m. Note that that (h) is measured up from the un-stretched position of the spring and not from the point where the collision occurs. | |
| Dec 2, 2021 at 18:54 | comment | added | d_b | No, that is not correct. The hanging block is in equilibrium, which means the spring must be exerting an upward force on the block to keep it from falling under the influence of gravity. So the spring cannot be at its equilibrium length. | |
| Dec 2, 2021 at 17:45 | comment | added | Sebastian Pojman-Malo | That's interesting. College Board (and I) assume that it absolutely does hit the original block when the spring is at its equilibrium. | |
| Dec 2, 2021 at 17:38 | comment | added | d_b | @SebastianPojman-Malo When I plugged the numbers into Mathematica, it spit out 14.5 something, and I rounded to two sig figs. In my answer, I'm taking into account the fact that the spring does not start at its equilibrium length. | |
| Dec 2, 2021 at 17:23 | comment | added | Sebastian Pojman-Malo | h=15 cm? I got 0.1447. Is this the same thing? Also, how does your equation differ from the one my teacher and I made, which outputs 24 centimeters? | |
| Dec 1, 2021 at 21:44 | history | edited | d_b | CC BY-SA 4.0 |
fixed typo in an equation
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| Dec 1, 2021 at 21:35 | history | answered | d_b | CC BY-SA 4.0 |