Timeline for Is the momentum operator in position basis a first-order approximation?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Nov 18, 2021 at 16:31 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
edited body; edited title; edited tags
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| Nov 18, 2021 at 16:30 | vote | accept | catmousedog | ||
| Nov 18, 2021 at 16:25 | answer | added | J. Murray | timeline score: 3 | |
| Nov 18, 2021 at 16:08 | comment | added | Quantum Mechanic | In this sense, momentum generates infinitesimal changes in position. This is not an approximation - the approximation comes in when you want to relate two positions that are not infinitesimally close to each other by only considering the momentum operator in the Taylor series. | |
| Nov 18, 2021 at 15:41 | history | asked | catmousedog | CC BY-SA 4.0 |