It is true only if the capacitors have capacitance values that are symmetric ( C1=C2 and C3=C4 ). Else is not true. You can do the computation using the formula of a series of capacitors 1/Ctot=1/C1+1/C2+...+1/Cn (here n=2), you can compute the charge by the well known relationship Q=C*V.

It is true, only if the capacitors have capacitance values that are symmetric ( $C_1 = C_2$ and $C_3 = C_4$ ). Else is not true. You can do the computation using the formula of a series of capacitors $1/C_{tot} = 1/C_1 + 1/C_2 +...+ 1/C_n$ (here $n = 2$). You can compute the charge by the well known relationship $Q = C \times V$.