Timeline for What is wrong with deriving length contraction from the spacetime interval in this way?
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Nov 12, 2021 at 12:14 | vote | accept | William Oliver | ||
| Nov 12, 2021 at 11:54 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
added 1 character in body; edited tags; edited title
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| Nov 12, 2021 at 8:47 | history | edited | jng224 | CC BY-SA 4.0 |
formatting
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| Nov 12, 2021 at 8:03 | answer | added | user12262 | timeline score: 1 | |
| Nov 11, 2021 at 22:32 | answer | added | Professor Sushing | timeline score: 1 | |
| Nov 11, 2021 at 1:58 | comment | added | user65081 | It is not necessary, I am glad it helped you. | |
| Nov 11, 2021 at 1:57 | comment | added | William Oliver | @Wolphramjonny If you put this in an answer I will accept it | |
| Nov 11, 2021 at 1:54 | comment | added | user65081 | the flashing will be out of synch in one of the two refernce frames. What you do to measure the lenght is to mark in your axis the locations of both the front and the end of the stick simultaneously in your reference system. nobody needs to move. so dtb is zero, forget about the flashes. dta is also zero. but you cannot equate the intervals dsa and dsb because they are not the same, the measurements of the front and back of the stick do not correspond to the same two events in the two reference systems. | |
| Nov 11, 2021 at 1:40 | comment | added | William Oliver | @Wolphramjonny took me a while to wrap my head around it, but I see what you are saying now. You mean that dtb in this case is the time between the two flashes, but not the time it takes for the measuring stick to move from point a to point b. I.e. this reasoning implicitly assumes that the flashes are simultaneous in Bob's frame. Is that right? | |
| Nov 11, 2021 at 1:07 | comment | added | user65081 | For lenght contraction both, dta and dtb must be zero, you can have this because the intervals are not equal, as you can easily see in a minkowski diagram. The measurements are simultaneous in both frames of reference. | |
| Nov 11, 2021 at 0:55 | history | asked | William Oliver | CC BY-SA 4.0 |