Timeline for Verifying conformal generators generate conformal transformations
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 22, 2021 at 16:29 | comment | added | Prahar | No. It holds in any signature. There are infinitely many terms in the correction. The exponential function has a whole Taylor expansion that you need to use to derive the action in D. you can’t just stop at the linear or quadratic level. | |
| Oct 22, 2021 at 16:18 | comment | added | 11Elves | Thats only because we're in euclidean spacetime, right? Isn't the correction $(x^\mu\partial_\mu)^2$? | |
| Oct 22, 2021 at 14:19 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
added 4 characters in body; edited tags
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| Oct 22, 2021 at 13:38 | answer | added | Cosmas Zachos | timeline score: 4 | |
| Oct 22, 2021 at 12:50 | comment | added | Prahar | Your action of $D$ is incorrect. The corrections are $O((x \cdot \partial)^2)$ which contains a linear term as well so act non-trivially on $x^\nu$. You cannot neglect them. PS - you need $( x \cdot \partial )^n x^\mu = x^\mu$ for any $n$. | |
| S Oct 22, 2021 at 11:05 | review | First questions | |||
| Oct 22, 2021 at 11:19 | |||||
| S Oct 22, 2021 at 11:05 | history | asked | 11Elves | CC BY-SA 4.0 |