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Oct 16, 2021 at 11:02 comment added Prahar Note that for numbers, complex conjugation is the same as conjugate transpose so $(A,B)^* = tr(A^\dagger B)^* = tr(A^\dagger B)^\dagger = tr ( [ A^\dagger B ]^\dagger ) = tr ( B^\dagger A) = (B,A)$.
Oct 16, 2021 at 8:20 history edited Qmechanic
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Oct 16, 2021 at 7:33 answer added Davide Morgante timeline score: 4
Oct 16, 2021 at 5:53 history edited Qmechanic CC BY-SA 4.0
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Oct 16, 2021 at 5:52 history edited eeqesri CC BY-SA 4.0
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Oct 16, 2021 at 5:41 history asked eeqesri CC BY-SA 4.0