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Oct 12, 2021 at 6:29 vote accept Arnab
Oct 11, 2021 at 22:40 comment added ZeroTheHero I think this misses (partially) the point: you are not using the right tool when you should be enforcing the boundary conditions.
Oct 11, 2021 at 22:27 answer added J. Murray timeline score: 3
Oct 11, 2021 at 21:59 history edited Arnab CC BY-SA 4.0
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Oct 11, 2021 at 21:48 comment added Arnab Just consider the repeated version of the solutions outside the well. Note I am only concerned about the behaviour inside the well. Or if you want-- you can make the width "a" go to infinity and use Fourier transform.
Oct 11, 2021 at 21:33 history edited Qmechanic
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Oct 11, 2021 at 21:23 comment added ZeroTheHero The solution for the infinite well are certainly not periodic since $\psi$ is $0$ outside the well, so why do you want to use FS in the first place?
Oct 11, 2021 at 20:59 history asked Arnab CC BY-SA 4.0