Timeline for What is the exchange particle in this Feynman diagram?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Oct 5, 2021 at 14:17 | vote | accept | FShrike | ||
| Oct 5, 2021 at 14:11 | answer | added | rob♦ | timeline score: 2 | |
| Oct 5, 2021 at 14:10 | history | edited | Qmechanic♦ |
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| Oct 5, 2021 at 14:09 | answer | added | Andrew | timeline score: 1 | |
| Oct 5, 2021 at 13:50 | comment | added | FShrike | @rob my teacher's diagram is wrong then? Are you suggesting that the positron arrives to meet the electron backward through time? I'm confused! The electron and positron should move together in time until they collide and annihilate, ... right? | |
| Oct 5, 2021 at 13:47 | comment | added | rob♦ | Note (also hint): the arrow on the positron should point towards the past, not the future. | |
| Oct 5, 2021 at 13:46 | comment | added | FShrike | So when the photon is emitted on the left-hand vertex, that's actually wrong, and both photons should instead be emitted from the righthand vertex at the incidence of the positron and electron? I thought particle-antiparticle pairs had to physically meet and collide to annihilate, and your comment seems to back this up, so is the electron that is decaying into a photon on the left ill-placed? @QuantumEyedea | |
| Oct 5, 2021 at 13:43 | comment | added | QuantumEyedea | The interaction vertex has two electrons and one photon always: this means the only thing it can be is an electron. | |
| S Oct 5, 2021 at 13:41 | review | First questions | |||
| Oct 5, 2021 at 13:43 | |||||
| S Oct 5, 2021 at 13:41 | history | asked | FShrike | CC BY-SA 4.0 |