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Oct 2, 2021 at 1:15 comment added Adam Herbst +1 I think this is definitely helpful, but I'm not convinced -- given two $\vec E$ fields, couldn't we just construct a $\vec J$ field for each one, such that the two volume integrals match? That's a specific instance of power consumption for a certain $\vec J$ field, not necessarily a measure of the entire power available in the $\vec E$ field.
Oct 1, 2021 at 7:59 history edited Cyrus Tirband CC BY-SA 4.0
clarification
Oct 1, 2021 at 7:54 history answered Cyrus Tirband CC BY-SA 4.0