Timeline for Relativistic factor between coordinate acceleration and proper acceleration
Current License: CC BY-SA 3.0
11 events
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Feb 9, 2019 at 16:35 | comment | added | Philip Wood | This is SO useful. Thank you. Notation is a challenge, is it not? I like $\vec u$ for $\frac{d \vec r}{dt}$ and $\vec U$ for the 3-vector proper velocity $\frac {d\vec r}{d \tau} $ and $\mathbf{U}$ for the four vector $(\gamma c,\ \vec U)$ but the accelerations are a nightmare... | |
Jan 8, 2018 at 17:12 | comment | added | inya | @Pulsar is this proper acceleration, as you have defined it, also the acceleration a particle will 'feel' in it's own instantaneous rest frame? | |
Jun 17, 2013 at 10:50 | comment | added | Pulsar | @diffeomorphism I've written an explanation in this post: physics.stackexchange.com/a/68331/24142 | |
Jun 15, 2013 at 8:53 | comment | added | Calmarius | So does this mean the acceleration felt by an accelerating observer is $du/dt$, and not $du/d\tau$? Isn't the local accelerometer measures $du/d\tau$? | |
Jun 3, 2013 at 0:05 | comment | added | diffeomorphism | shouldn't the module of the non-inertial forces in the accelerated frame be defined as a Lorentz-invariant scalar? if the frame feels one-G, that one-G should be agreed by all observers, instead you are saying that the proper acceleration is a derivative of coordinate time, not proper time, so a different coordinate system will measure a different G-force on that frame. How is that possible? | |
Jun 2, 2013 at 20:51 | history | edited | Pulsar | CC BY-SA 3.0 |
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Jun 2, 2013 at 20:24 | history | edited | Pulsar | CC BY-SA 3.0 |
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Jun 2, 2013 at 20:16 | comment | added | Pulsar | His mistake is that he confuses proper acceleration with four-vector acceleration. I explained that these are two different quantities. | |
Jun 2, 2013 at 20:13 | comment | added | Larry Harson | This doesn't answer the question. He wants to know where he's made a mistake in his working | |
Jun 2, 2013 at 20:11 | history | edited | Pulsar | CC BY-SA 3.0 |
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Jun 2, 2013 at 20:04 | history | answered | Pulsar | CC BY-SA 3.0 |