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Sep 15, 2021 at 0:11 history closed d_b
John Rennie
Voulkos
Michael Seifert
ZeroTheHero
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Sep 14, 2021 at 19:38 history edited Voulkos CC BY-SA 4.0
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Sep 14, 2021 at 19:35 answer added xXx_69_SWAG_69_xXx timeline score: 1
Sep 14, 2021 at 19:14 comment added Voulkos Related : What is the electric field flux through the base of a cube from a point charge infinitesimally close to a vertex?.
Sep 14, 2021 at 18:49 comment added Philip Wood If it were the $z=4$ m plane it would be so easy!
Sep 14, 2021 at 17:47 review Close votes
Sep 15, 2021 at 0:11
Sep 14, 2021 at 17:41 comment added Sumit Gupta Say you considered vacuum. Then the equation would be $\Psi = \oint \vec{E}\cdot \vec{da}$. Assume small area $dxdy$ on the plane. This area points in the $z$ direction. Calculate $\vec{E}$ for some general point $(x, y, z_0)$. Evaluate the flux $\oint Eda\cos\theta$ involving double integrals with the limits for $x$ and $y$ given.
Sep 14, 2021 at 17:35 comment added garyp There are two things that need sorting out. Are you looking for electric field flux or displacement field flux? By context I think you are looking for displacement field flux. If you can't think of a way to calculate ${\bf D}$ directly, perhaps you can find it another way. You would have to make the reasonable assumption that the problem lies in a vacuum.
S Sep 14, 2021 at 17:23 review First questions
Sep 14, 2021 at 17:25
S Sep 14, 2021 at 17:23 history asked yntkts CC BY-SA 4.0