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Acceleration at rest How can acceleration $a$ be zero when applied force $F$ is non-zero?

An object is at rest and stays at rest, but an attached rope pulls with increasing force. What is the acceleration?

The correct solution is that acceleration is constant and 0. Obviously a= dv/dt =0$a= dv/dt =0$, since the object is at rest.

But if force is increasing, since F=ma$F=ma$, isn't acceleration increasing as well? If the two are directly related, why does acceleration not increase along with increasing force?

Acceleration at rest

An object is at rest and stays at rest, but an attached rope pulls with increasing force. What is the acceleration?

The correct solution is that acceleration is constant and 0. Obviously a= dv/dt =0, since the object is at rest.

But if force is increasing, since F=ma, isn't acceleration increasing as well? If the two are directly related, why does acceleration not increase along with increasing force?

How can acceleration $a$ be zero when applied force $F$ is non-zero?

An object is at rest and stays at rest, but an attached rope pulls with increasing force. What is the acceleration?

The correct solution is that acceleration is constant and 0. Obviously $a= dv/dt =0$, since the object is at rest.

But if force is increasing, since $F=ma$, isn't acceleration increasing as well? If the two are directly related, why does acceleration not increase along with increasing force?

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Acceleration at rest

An object is at rest and stays at rest, but an attached rope pulls with increasing force. What is the acceleration?

The correct solution is that acceleration is constant and 0. Obviously a= dv/dt =0, since the object is at rest.

But if force is increasing, since F=ma, isn't acceleration increasing as well? If the two are directly related, why does acceleration not increase along with increasing force?