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Aug 18, 2021 at 11:51 vote accept Mauricio
Aug 18, 2021 at 11:18 answer added user87745 timeline score: 5
Aug 18, 2021 at 11:02 comment added Mauricio @ValterMoretti Is more of a definition, the problem is that $A$ is not your usual matrix because it is antilinear.
Aug 18, 2021 at 11:02 history edited Mauricio CC BY-SA 4.0
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Aug 18, 2021 at 11:00 comment added Valter Moretti I agree with the other comments: it is not possible to use only anti unitary operators. However, this identity $A|\psi \rangle = |A\psi \rangle$ is obscure, I cannot interpret it.
Aug 18, 2021 at 10:39 comment added jacob1729 You can't make the time evolution operator $U(t)$ anti-unitary for all $t$ since $U(0)$ needs to be the identity.
Aug 18, 2021 at 10:34 history edited Mauricio CC BY-SA 4.0
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Aug 18, 2021 at 10:33 comment added Mauricio @AccidentalFourierTransform Good point.
Aug 18, 2021 at 10:29 history edited Qmechanic CC BY-SA 4.0
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Aug 18, 2021 at 10:29 comment added AccidentalFourierTransform There is no theory with only anti-unitaries. The product of two anti-unitaries is always unitary.
S Aug 18, 2021 at 10:26 history suggested Jakeup CC BY-SA 4.0
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Aug 18, 2021 at 10:25 review Suggested edits
S Aug 18, 2021 at 10:26
Aug 18, 2021 at 10:22 history edited Mauricio CC BY-SA 4.0
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Aug 18, 2021 at 10:10 history asked Mauricio CC BY-SA 4.0