Timeline for Am I making a fatal error with this simplification?
Current License: CC BY-SA 4.0
26 events
| when toggle format | what | by | license | comment | |
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| Aug 18, 2021 at 3:01 | review | Close votes | |||
| Aug 19, 2021 at 3:01 | |||||
| Aug 16, 2021 at 4:51 | history | edited | Qmechanic♦ |
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| Aug 16, 2021 at 3:28 | history | edited | rdotrose | CC BY-SA 4.0 |
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| Aug 15, 2021 at 21:30 | comment | added | TCooper | @KingLogic Sorry to be so pedantic, I push because I never know if there’s specific terminology used in a field I’m relatively foreign to - I didn’t want to exclude that could be a very common phrasing, and for good reason I couldn’t see. | |
| Aug 15, 2021 at 1:36 | comment | added | KingLogic | @TCooper yeah sorry my bad for causing confusion, I meant Cylinder volume / 3 = Cone volume | |
| Aug 13, 2021 at 15:39 | comment | added | TCooper | @KingLogic Right, I guess your wording in the first comment threw me off. I've always considered the phrase "x's volume(v) 'goes into' y's v m times" to be imply xvm = yv. I've never really seen 'goes into' used with, what to me, is the opposite meaning. 2 goes into 6 3 times, but 6 doesn't go into 2 3 times, no? | |
| Aug 13, 2021 at 0:03 | comment | added | KingLogic | @TCooper cone volume = cylinder volume / 3, or cone can be completely filled and pour into cylinder, 3 times. | |
| Aug 12, 2021 at 23:26 | comment | added | TCooper | @KingLogic Did you mean the cone's volume goes into the cylinders volume three times? | |
| Aug 12, 2021 at 16:31 | comment | added | RLH | Glasses with cylindrical outsides and conical insides (historically used to provide bar patrons with less beverage than they thought they were getting, context may need to be adapted for age appropriateness) provide a cylinder/cone volume comparison without needing to consider flow rate. | |
| Aug 12, 2021 at 8:39 | comment | added | Alwin | I just want to say, I think it's wonderful that you are thinking of interesting problems to pose, putting in great effort, and even vetting those problems by asking online strangers! This one might not be perfect, but I hope you keep it up :). Maybe you can do something with the volume of fuel/burn duration of a rocket/firework with cylindrical bottom and conical top, or a sand-filled hourglass, and pretend like the flow rate is constant. | |
| Aug 12, 2021 at 1:01 | comment | added | KingLogic | For 9th graders learning about geometry, I would maybe try to see if I can find a cylindrical and a conical container, both of which have the same height and same opening radius. Then use water to pour to prove that the cylinder's volume goes into the cone's volume 3 times. | |
| Aug 11, 2021 at 21:47 | history | became hot network question | |||
| Aug 11, 2021 at 19:21 | review | Close votes | |||
| Aug 12, 2021 at 12:11 | |||||
| S Aug 11, 2021 at 18:38 | history | suggested | ACB | CC BY-SA 4.0 |
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| Aug 11, 2021 at 18:15 | review | Suggested edits | |||
| S Aug 11, 2021 at 18:38 | |||||
| Aug 11, 2021 at 18:14 | answer | added | Quantum Mechanic | timeline score: 1 | |
| Aug 11, 2021 at 16:30 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
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| Aug 11, 2021 at 15:01 | comment | added | J. Murray | Though this particular concept may not quite fit with your intention, note that it presents an excellent opportunity to discuss the fact that "average" is an overloaded term. Do you mean the average over the length of the cone, or the average over the volume of the cone, or the average over time for a single fluid parcel? Michael's excellent answer illustrates how each of these might be computed. | |
| Aug 11, 2021 at 14:52 | comment | added | David White | The problem as stated is somewhat ambiguous without a drawing. Does the cone base attach to the hose or does the cone tip attach to the hose? What is the diameter of the hose, the diameter of the cone base and the diameter of the hole in the cone tip? Also, without knowing the continuity equation, the students are going to have a difficult time understanding the question's solution, and that equation guarantees that the water's velocity in the cone is not constant. This is a difficult example for a 9th grader to comprehend. | |
| Aug 11, 2021 at 14:31 | answer | added | Michael Seifert | timeline score: 4 | |
| Aug 11, 2021 at 14:17 | history | edited | rdotrose | CC BY-SA 4.0 |
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| Aug 11, 2021 at 14:10 | comment | added | Quantum Mechanic | Consider that the hose and the spout may have different lengths such that the 1/3 volume factor does not apply. As long as we have a flow rate, changing the length of the hose will not affect anything that happens at the spout. So the volume factor cannot be relevant here, unfortunately! | |
| Aug 11, 2021 at 14:01 | answer | added | gandalf61 | timeline score: 9 | |
| Aug 11, 2021 at 13:58 | answer | added | J. Murray | timeline score: 13 | |
| Aug 11, 2021 at 13:51 | review | First posts | |||
| Aug 11, 2021 at 13:57 | |||||
| Aug 11, 2021 at 13:47 | history | asked | rdotrose | CC BY-SA 4.0 |