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Aug 7, 2021 at 11:00 comment added Eli Lets take my case $~x_1(t)~,y_1(t)~y_2(t)$ are the generalized coordinates you obtain the EOM's and you have two configuration for the initial conditions the red one and the blue one the solution for blue IC is $x_2(t)=x_1(t)+\sqrt{L^2-(y_2(t)-y_1(t))^2}~$ and for the red IC is $x_2(t)=x_1(t)-\sqrt{L^2-(y_2(t)-y_1(t))^2}$, by giving the IC you decide which case you want to simulate? But I don't think is something wrong with this ?
Aug 7, 2021 at 9:12 comment added Anu3082 Say you found out three of the four co-ordinates $(x_1, x_2, y_1)$ by solving the differential equations whatever it may have been. How do you find out the fourth co-ordinate $y_2$? Won't there be two answers for it? Sure $y_2$ doesn't enter the DE's but can you be satisfied with two answers for $y_2$ once you have found out the rest?
Aug 6, 2021 at 14:53 history edited Eli CC BY-SA 4.0
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Aug 6, 2021 at 11:10 history edited Eli CC BY-SA 4.0
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Aug 6, 2021 at 10:29 history answered Eli CC BY-SA 4.0