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Aug 6, 2021 at 6:54 comment added Al Brown Yeah of course. My mistake. F=ma is not an eqn of motion. I wrote above that friction doesnt change it if coef of rolling friction is constant. Agree that??
Aug 6, 2021 at 6:50 comment added ACB @AlBrown, I meant: from first equation we can find $v$, then using $v^2=u^2+2aS$ we can find $a$.
Aug 6, 2021 at 6:26 comment added Al Brown You dont actually need equations of motion (if you mean f=ma and T=I $\omega ‘$). The energy will work. But maybe you meant v=$ \omega r$ , v=x’ , a=x’’ etc.
Aug 6, 2021 at 5:45 history edited Gert CC BY-SA 4.0
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Aug 6, 2021 at 3:44 history edited ACB CC BY-SA 4.0
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Aug 6, 2021 at 3:38 history edited ACB CC BY-SA 4.0
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Aug 6, 2021 at 3:32 history answered ACB CC BY-SA 4.0