Timeline for Does a larger ball of the same mass roll faster downhill than a smaller ball?
Current License: CC BY-SA 4.0
7 events
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Aug 6, 2021 at 6:54 | comment | added | Al Brown | Yeah of course. My mistake. F=ma is not an eqn of motion. I wrote above that friction doesnt change it if coef of rolling friction is constant. Agree that?? | |
Aug 6, 2021 at 6:50 | comment | added | ACB | @AlBrown, I meant: from first equation we can find $v$, then using $v^2=u^2+2aS$ we can find $a$. | |
Aug 6, 2021 at 6:26 | comment | added | Al Brown | You dont actually need equations of motion (if you mean f=ma and T=I $\omega ‘$). The energy will work. But maybe you meant v=$ \omega r$ , v=x’ , a=x’’ etc. | |
Aug 6, 2021 at 5:45 | history | edited | Gert | CC BY-SA 4.0 |
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Aug 6, 2021 at 3:44 | history | edited | ACB | CC BY-SA 4.0 |
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Aug 6, 2021 at 3:38 | history | edited | ACB | CC BY-SA 4.0 |
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Aug 6, 2021 at 3:32 | history | answered | ACB | CC BY-SA 4.0 |