Timeline for Can a single molecule have a temperature?
Current License: CC BY-SA 4.0
9 events
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Feb 2, 2019 at 18:56 | comment | added | anna v | @garyp I am familiar within this type of equipartiton which has no potential energy there.hyperphysics.phy-astr.gsu.edu/hbase/Kinetic/eqpar.html . In any case everything is about mean and average, even in your link,which needs more than one particle to manifest, imo | |
Feb 2, 2019 at 18:14 | comment | added | garyp | The equipartition theorem relates temperature to degrees of freedom that appear quadratically in the hamiltonian. So potential energy contributes as well, not just kinetic. For an ideal gas there is only kinetic energy so we get simplified treatments. However, I will admit that the entire subject of relating temperature to energy, and thermal energy vs. internal energy, leaves me somewhat confused. | |
May 22, 2018 at 8:28 | history | edited | Nat | CC BY-SA 4.0 |
added 176 characters in body
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Sep 29, 2017 at 7:27 | history | edited | stafusa | CC BY-SA 3.0 |
Added definition of "a".
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Apr 4, 2017 at 18:02 | comment | added | anna v | @WillO it is in the link alpha=sqrt(kT/m), three different temperatures distributions for a fixed mass. | |
Apr 4, 2017 at 13:32 | comment | added | WillO | The curves in the picture appear to be parameterized by something called $a$, but there is no $a$ in the equation they're presumably meant to illustrate. | |
May 24, 2013 at 8:24 | comment | added | gatsu | Sure but if you have one molecule coupled to a thermostat and the system is ergodic then the distribution you are talking about can be thought as being a frequency with which each state is visited over a very long period of time. For once ergodicty is useful in this case | |
May 24, 2013 at 4:31 | history | edited | Brandon Enright | CC BY-SA 3.0 |
Loose to lose
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May 24, 2013 at 4:04 | history | answered | anna v | CC BY-SA 3.0 |