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Feb 2, 2019 at 18:56 comment added anna v @garyp I am familiar within this type of equipartiton which has no potential energy there.hyperphysics.phy-astr.gsu.edu/hbase/Kinetic/eqpar.html . In any case everything is about mean and average, even in your link,which needs more than one particle to manifest, imo
Feb 2, 2019 at 18:14 comment added garyp The equipartition theorem relates temperature to degrees of freedom that appear quadratically in the hamiltonian. So potential energy contributes as well, not just kinetic. For an ideal gas there is only kinetic energy so we get simplified treatments. However, I will admit that the entire subject of relating temperature to energy, and thermal energy vs. internal energy, leaves me somewhat confused.
May 22, 2018 at 8:28 history edited Nat CC BY-SA 4.0
added 176 characters in body
Sep 29, 2017 at 7:27 history edited stafusa CC BY-SA 3.0
Added definition of "a".
Apr 4, 2017 at 18:02 comment added anna v @WillO it is in the link alpha=sqrt(kT/m), three different temperatures distributions for a fixed mass.
Apr 4, 2017 at 13:32 comment added WillO The curves in the picture appear to be parameterized by something called $a$, but there is no $a$ in the equation they're presumably meant to illustrate.
May 24, 2013 at 8:24 comment added gatsu Sure but if you have one molecule coupled to a thermostat and the system is ergodic then the distribution you are talking about can be thought as being a frequency with which each state is visited over a very long period of time. For once ergodicty is useful in this case
May 24, 2013 at 4:31 history edited Brandon Enright CC BY-SA 3.0
Loose to lose
May 24, 2013 at 4:04 history answered anna v CC BY-SA 3.0