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Qmechanic
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Briefly, theThe generator of $x$-translations is more precisely the $x$-derivative $\frac{\partial}{\partial x}=i\frac{\hat{p}}{\hbar}=i\hat{k}$,$$\frac{\partial}{\partial x}~=~i\frac{\hat{p}}{\hbar}~=~i\hat{k},$$ the wavenumber operator, which is independent of $\hbar$.

Briefly, the generator of $x$-translations is more precisely the $x$-derivative $\frac{\partial}{\partial x}=i\frac{\hat{p}}{\hbar}=i\hat{k}$, the wavenumber operator.

The generator of $x$-translations is more precisely the $x$-derivative $$\frac{\partial}{\partial x}~=~i\frac{\hat{p}}{\hbar}~=~i\hat{k},$$ the wavenumber operator, which is independent of $\hbar$.

Source Link
Qmechanic
  • 213.1k
  • 48
  • 590
  • 2.3k

Briefly, the generator of $x$-translations is more precisely the $x$-derivative $\frac{\partial}{\partial x}=i\frac{\hat{p}}{\hbar}=i\hat{k}$, the wavenumber operator.