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Feb 21, 2023 at 17:05 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Oct 20, 2022 at 15:03 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jul 24, 2021 at 17:41 comment added Uphill trajectory @KP99 I understand your point now. Much thanks!
Jul 23, 2021 at 10:20 comment added KP99 Charge is quantized, but one doesn't invoke such condition when calculating self energy in classical regime (Coulombic interaction doesn't imply charge quantisation). More correct interpretation comes from quantum electro dynamics, where self interaction comes from an electron interacting with its own virtual photons. Here charge is quantized, and involves both relativistic and quantum mechanical corrections to Coulombic interaction
Jul 23, 2021 at 9:57 answer added Himanshu timeline score: 1
Jul 23, 2021 at 9:52 history edited Uphill trajectory CC BY-SA 4.0
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Jul 23, 2021 at 9:22 comment added Uphill trajectory @KP99 i.e. I want to consider building the charge configuration from $e$ charges. Then the energy should should still come to $$\gamma\frac{1}{4\pi\epsilon_0}\frac{e^2}{r}$$ where $\gamma$ is some factor
Jul 23, 2021 at 9:13 comment added Uphill trajectory @KP99 but if you quantise charge, $dq$ can only as small as $e$
Jul 23, 2021 at 8:41 comment added KP99 $dq$ refers to any infinitesimal charge, not necessarily quantized charge $e$. It varies from system to system how small should $dq$ be. For an electron, you will have to assume $dq<<e$. For ordinary object $dq=e$ can be a good approximation. The point is dq must be much smaller than the total charge Q.
Jul 23, 2021 at 8:16 history edited Vincent Thacker CC BY-SA 4.0
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Jul 23, 2021 at 8:15 review First posts
Jul 23, 2021 at 8:19
Jul 23, 2021 at 8:15 history asked Uphill trajectory CC BY-SA 4.0