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Jul 16, 2021 at 0:37 comment added ZeroTheHero … and so such functions in $\mathbb{R}^3$ are possible to represent spin states.
Jul 15, 2021 at 23:50 comment added ZeroTheHero Actually angular momentum does not act (algebraically) in $L^2(\mathbb{R}^3)$, but in a direct sum of Hilbert spaces of different dimensions. The Hilbert space of dimension $2j+1$ occurs exactly $2j+1$ times in the full Hilbert space by Peter-Weyl theorem. Basis functions can be chosen to be in terms of real coordinates, but the choice of basis functions is inessential to the formalism of QM.
Jul 15, 2021 at 23:23 answer added Brian Bi timeline score: 1
Jul 15, 2021 at 19:24 comment added anna v If elementary particles were not assigned a spin, conservation of angular momentum would not hold at quantum level interactions.. The assignement in the table is consistent with angular momentum conservation at the quantum level en.wikipedia.org/wiki/Elementary_particle
Jul 15, 2021 at 17:47 vote accept ric.san
Jul 15, 2021 at 17:37 history edited SuperCiocia CC BY-SA 4.0
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Jul 15, 2021 at 17:35 answer added SuperCiocia timeline score: 1
Jul 15, 2021 at 16:42 history asked ric.san CC BY-SA 4.0