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Jul 30, 2021 at 11:32 answer added LL 3.14 timeline score: 1
Jul 16, 2021 at 15:17 comment added jwimberley A complete non-sequitur, but I was not familiar with Wigner functions or quasiprobability. In experimental high energy physics, a statistical technique called sPlots, used in background subtraction in multidimensional data where there is a "control" variable with good s/b distinguishability, and which also happens to involve taking expectations with "sWeights" (selecting whether an event belongs to signal or background) that may be negative. I wonder whether these sPlots could be expressed in a quasi-probability like formalism. arxiv.org/pdf/physics/0602023.pdf
Jul 15, 2021 at 14:57 history edited Cosmas Zachos
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Jul 15, 2021 at 14:07 answer added Cosmas Zachos timeline score: 2
Jul 14, 2021 at 23:27 comment added Quantum Mechanic More importantly: when you measure any operator you can calculate $\langle \hat{G}\rangle=\int dx dp W(x,p) g(x,p)$, where $g(x,p)$ is the Wigner transform of $\hat{G}$, so that is the sense in which $W(x,p)$ forms a probability distribution (intuitively: regions of larger $|W|$ are more heavily weighted in calculating $\langle \hat{G}\rangle$).
Jul 14, 2021 at 23:25 comment added Quantum Mechanic If integration over one of two axes in phase space is infinite, we recover the marginal probability distribution for the other axis, so the second integral correctly predicts the (true) probability of finding the particle within that second linear region of integration (eg if the bounds on $p$ are infinite we will get the true probability of finding the $x$ value to be within its integration range). If we reduce this infinite integral to a smaller region that still includes most of the nonzero probability in the Wigner function, the above still holds approximately
Jul 14, 2021 at 23:12 history asked The_Sympathizer CC BY-SA 4.0