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Jul 9, 2021 at 12:34 comment added Simo Kivistö @rcgldr well, your example is almost identical to the one in this answer except that the acceleration is angular (hopefully I'm using the correct term) and you feel the inertia of your organs as they are "trying" to continue with their direct path. So the organs feel the centripetal force of the surrounding tissue. The surrounding tissue feels the reactive force that the organs exert on other objects.
Jul 9, 2021 at 10:50 comment added rcgldr @SimoKivistö - A person can feel internal reactive centrifugal force, blood, organs, and the compression due to centripetal force and the reactive centrifugal force. Newton third law pairs refer to the force each object exerts on the other, one of them being a reactive force due to acceleration.
Jul 9, 2021 at 8:53 comment added Simo Kivistö @rcgldr OP mentions: "The object at the non-inertial frame really feels the centrifugal force!" so they seem to be talking about forces on the object. The wiki article speaks about the force exerted by that object: "there will also be an equal and opposite force exerted by the object on some other object [...] sometimes called a reactive centrifugal force"
Jul 9, 2021 at 4:45 comment added rcgldr The last part of the OP's question is "So, is it really right to call centrifugal force fictitious just because it doesn't exist in an inertial reference frame?". My impression is that the OP is asking about centrifugal force in an inertial reference frame, in which case reactive centrifugal force is a real force, not fictitious. Link to wiki article .
Jul 8, 2021 at 16:21 vote accept tryingtobeastoic
Jul 8, 2021 at 14:44 comment added Vincent Thacker @AbuSafwan In GR, gravity is a result of curved spacetime and geodesics, so it is not a source of proper acceleration. However, if an observer has non-zero proper acceleration, objects nearby will appear to have a fictitious (coordinate) acceleration. The easiest example is the surface of the Earth. The surface of the Earth is accelerating radially outwards with proper acceleration $g$, so we see freely-falling objects "accelerate" at $-g$. See my answer here.
Jul 8, 2021 at 14:38 comment added tryingtobeastoic @VincentThacker but fictitious force wiki says otherwise, what am I understanding wrong?
Jul 8, 2021 at 14:37 comment added tryingtobeastoic @VincentThacker Fictitious forces, or physics whose cause is outside of the system, are no longer necessary in general relativity, since these physics are explained with the geodesics of spacetime. - en.wikipedia.org/wiki/Fictitious_force#Background
Jul 8, 2021 at 14:35 comment added Vincent Thacker @AbuSafwan Yes, because proper acceleration cannot be set to zero by a coordinate transformation.
Jul 8, 2021 at 14:28 comment added tryingtobeastoic @VincentThacker If I use general relativity, do I still need to use pseudo forces?
Jul 8, 2021 at 14:27 comment added Vincent Thacker @AbuSafwan No, or else you won't obtain the correct equations of motion.
Jul 8, 2021 at 13:52 comment added tryingtobeastoic @VincentThacker Is there a way to avoid using pseudo forces in a non-inertial frame of reference?
Jul 8, 2021 at 13:51 comment added Vincent Thacker @AbuSafwan Choose an inertial frame. This can be physically achieved by using accelerometers to determine whether you, as an observer, are accelerating or not. A weighing scale is an example of an (single-directional) accelerometer.
Jul 8, 2021 at 13:45 comment added tryingtobeastoic If I want to avoid using pseudo forces altogether, what do I have to do?
Jul 8, 2021 at 12:59 comment added Professor Sushing @RogerVadim indeed, a point well made.
Jul 8, 2021 at 11:55 comment added Roger V. Note that mechanical phenomena can be discussed in non-inertial frames of reference just as well as in the inertial ones, provided that one introduces appropriate pseudoforces (centrifugal force, Koriolis force, Euler force, etc.)
Jul 8, 2021 at 10:57 history answered Professor Sushing CC BY-SA 4.0