Since the characteristic time of diffusion is $L^2/D$L²/D, where $L$L is the characteristic length and $D$D is the diffusivity (here, the thermal diffusivitythermal diffusivity), the characteristic speed is $D/L$D/L, or $10^{-7}\,\mathrm{m/s}$10-7 m/s for a 1 km deep probe and very thermally conductive copper. We can pump liquid at speed v far faster than this.
Looking at the conductive power delivery, we have kAΔT/L for the probe, where k is the thermal conductivity, A is the cross-sectional area and ΔT is the temperature difference. Compare this to ρCVΔT/t for advective transfer, where ρ is the material density, C is its specific heat capacity, V is its volume, and t is the turnaround time. Dividing by AΔT, we’re comparing the magnitudes of k/L and ρCv. Again, wewhere v is the liquid pumping speed. We find again that v need only exceed 10-7 m/s for water to best a strongly conductive rod.
The conclusion is that when L is large (or even longer than millimeters), that pumping liquid is generally a far more effective way to transfer thermal energy than to rely on conduction.
(I’ll leave it to you to incorporate the relevant cost comparison, which takes this topic into engineering.)