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May 20, 2013 at 11:04 comment added Siva @Tariq: Usually, heat from a hotter to a colder body since that is statistically/thermodynamically preferred. I think that in this case, the evaporating water can't get heat from the atmosphere (since it's probably not interacting much with the environment before it evaporates) and hence, must get heat from the pot.
May 20, 2013 at 10:32 history edited RedGrittyBrick CC BY-SA 3.0
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May 20, 2013 at 10:26 comment added RedGrittyBrick This is how I understand it: Evaporative cooling can reduce the temperature of some object to below ambient temperature. Evaporation is an endothermic process that removes energy from the object. Molecules in a liquid are constantly colliding and transferring energy back and forth. Water molecules leaving the surface have higher energy than molecules remaining in the liquid state. These higher energy molecules have left the liquid and can no longer transfer that higher energy back to the other molecules. The remaining molecules collectively have less energy.
May 20, 2013 at 9:14 comment added Tariq I'm afraid I didn't understand it yet. As fas as I know is that heat flows from body of high temperature to the body of low temperature. On the other hand, my concern is about the current temperature of water inside the pot; would it decrease further if temperature outside were higher?
May 16, 2013 at 11:00 comment added RedGrittyBrick See Matki "The cooling process works through evaporative cooling. Water seeps from mini-pores in the pot and evaporates, thus making the water inside cooler than the outside temperature"
May 16, 2013 at 10:48 comment added Tariq Thanks RedGrittyBrick, but how would the pot be at lower temperature if the environment temperature is higher (assuming summer times)?
May 15, 2013 at 21:45 history answered RedGrittyBrick CC BY-SA 3.0