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Jun 6, 2021 at 4:25 history edited oliver CC BY-SA 4.0
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Jun 6, 2021 at 4:18 comment added oliver ... in other words, figuratively speaking, if you expose the circuit to a nuclear explosion, it will disintegrate, and hence, the charge distribution will certainly have an effect on the speed of the signal in the wire.
Jun 6, 2021 at 4:18 comment added oliver These effects will be part of the low frequency limit of the Drude-Lorentz model (the conductivity part). It is determined mainly by the configuration of the atom bodies and the bulk of the electrons, not the small amount of surface charges. However, it is easy to imagine that, if charge distribution gets extreme enough, it will cause the model to break down, and hence, change the whole dispersion relation in an arbitrary way...
Jun 6, 2021 at 4:08 comment added Predaking Askboss So, is there any effect of charge distribution to the speed of signal in wire? Because the signal itself is travelling due to the charges setup in wire and electrons have mass too and a very low drift velocity. In this way one electrons moves a little and it electric field propagates and then the next charge moves a little and and so on. This will affect the speed of electricity even the electrons have to cover a very less distance.
Jun 6, 2021 at 4:07 history edited oliver CC BY-SA 4.0
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Jun 6, 2021 at 4:01 history answered oliver CC BY-SA 4.0