Timeline for Why don't we take $r$ as equal to the radius in the spherical coordinate system?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Jun 1, 2021 at 6:45 | answer | added | gandalf61 | timeline score: 0 | |
| Jun 1, 2021 at 6:33 | comment | added | G. Smith | the radius for a differential equation What does a differential equation have to do with this integral? | |
| Jun 1, 2021 at 6:17 | comment | added | G. Smith | It’s the distance from the infinitesimal element of charge $dq=\rho d\tau$ located at $(r,\theta,\phi)$ to the point where you are computing the potential it creates. All the charge of the ball is not at the origin; it is uniformly distributed throughout the ball. | |
| Jun 1, 2021 at 6:15 | answer | added | Himanshu | timeline score: 0 | |
| Jun 1, 2021 at 6:07 | review | First posts | |||
| Jun 1, 2021 at 6:41 | |||||
| Jun 1, 2021 at 6:05 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
added 10 characters in body; edited tags; edited title
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| Jun 1, 2021 at 6:03 | history | asked | Nabasindhu Das | CC BY-SA 4.0 |