Timeline for Operator acting on tensor product of states
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
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| Sep 4 at 23:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Apr 30 at 23:08 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Dec 24, 2023 at 22:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Aug 22, 2023 at 5:02 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Apr 23, 2023 at 6:07 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Dec 21, 2022 at 0:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Aug 16, 2022 at 0:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Apr 10, 2022 at 10:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| May 9, 2021 at 15:07 | history | edited | ZeroTheHero | CC BY-SA 4.0 |
added 55 characters in body
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| May 8, 2021 at 17:37 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
added 6 characters in body; edited tags
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| May 8, 2021 at 16:42 | answer | added | Cosmas Zachos | timeline score: 0 | |
| May 8, 2021 at 15:51 | comment | added | Cosmas Zachos | Linked and this answer. | |
| May 8, 2021 at 15:38 | comment | added | Cosmas Zachos | Your notation is highly unconventional... indeed, freaky. There is no general recipe for a generic operator $\hat O$; if it were an angular momentum component, your expression would be right. If a Casimir invariant, very wrong. | |
| May 8, 2021 at 13:21 | history | asked | Mr Lolo | CC BY-SA 4.0 |