Timeline for How to find the falling time of an object when acceleration is not a constant?
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Apr 21, 2021 at 2:31 | comment | added | Dheeraj Kumar | @Philip Yes,thanks I edited now | |
| Apr 21, 2021 at 2:30 | history | edited | Dheeraj Kumar | CC BY-SA 4.0 |
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| Apr 20, 2021 at 21:16 | comment | added | Philip | @DheerajKumar I assume you mean $$-\frac{GMm}{x},$$ which is the potential energy, otherwise your first equation is not dimensionally correct... | |
| Apr 20, 2021 at 11:15 | comment | added | Dale | @Majd if you don’t know calculus then you cannot do this. Calculus was invented specifically for this type of problem | |
| Apr 20, 2021 at 10:48 | review | First posts | |||
| Apr 20, 2021 at 11:11 | |||||
| Apr 20, 2021 at 10:25 | comment | added | Majd | i am not that familiar with calculus , is there anyway u can continue your solution and provide a full solution so i can understand ? | |
| Apr 20, 2021 at 10:22 | history | edited | jng224 | CC BY-SA 4.0 |
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| Apr 20, 2021 at 10:19 | comment | added | Dheeraj Kumar | if you know a bit about differential calculus, dx/dt is the derivative of x with respect to time and it denotes the instantaneous change in displacement wrt time which is the instantaneous velocity. | |
| Apr 20, 2021 at 10:14 | comment | added | Majd | okay i understand the first part where u find the C1 , but im not quite sure what to do after ? i didn't understand the part of -dx/dt thing | |
| Apr 20, 2021 at 10:09 | comment | added | Dheeraj Kumar | Edits are encouraged if someone can make my solution more clear by typesetting etc. | |
| Apr 20, 2021 at 10:04 | history | answered | Dheeraj Kumar | CC BY-SA 4.0 |