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Apr 14, 2021 at 19:47 vote accept Another User
Apr 14, 2021 at 19:37 answer added ytlu timeline score: 3
Apr 14, 2021 at 19:35 history edited Another User CC BY-SA 4.0
Found part of the answer
Apr 14, 2021 at 13:52 comment added Another User I know. The integrals can be put in one form using indices, but I won't write it. I have derived it myself, following my teacher and the book. I know this is right. I don't have to convince you otherwise. Luckily going once more through the book I found my answer. So thanks, I guess
Apr 14, 2021 at 13:49 comment added ytlu The integrals are quadrupole terms, the potential is in the front factor. You may read on more equation.
Apr 14, 2021 at 13:46 comment added Another User The PDF clearly agrees with my definition. See the equation after equation (20)
Apr 14, 2021 at 13:45 comment added ytlu I don't have this book. Read the pdf, it uses traceless quadupole. Even the wiki also say that both forms gives the same potential function.
Apr 14, 2021 at 13:44 comment added Another User Read my book then. Zangwill Section 4.4. Don't see any mistakes
Apr 14, 2021 at 13:44 comment added ytlu static1.squarespace.com/static/570e7b14e707ebd28d391286/t/…
Apr 14, 2021 at 13:43 comment added ytlu No. The potential is the same form, even if you using traceless form of quadrupole.
Apr 14, 2021 at 13:42 comment added Another User I read the article and it doesn't even use the non-traceless tensor apart from giving the definition. In my book there's an explicit derivation. Also, it's quite obvious that if the tensor changes the corresponding potential will change too (sometimes this is may not be true since something gets smplified). In fact the change is "symmetric", if you look at the both versions of the tensor and the potential
Apr 14, 2021 at 13:37 comment added ytlu Check the second paragraph en.wikipedia.org/wiki/Quadrupole
Apr 14, 2021 at 13:35 comment added ytlu Not the potential from a quadrupole. You are talking the form of the quadrupole.
Apr 14, 2021 at 13:34 comment added Another User You can use different tensors. The one you used is traceless if I remember correctly
Apr 14, 2021 at 13:33 comment added ytlu The potential from a quadrupole $V(\vec r) = \frac{k}{2r^5} \sum_i\sum_j Q_{ij} x_i x_j$. Seemly, you mixed the potential with the quadrupole definition.
Apr 14, 2021 at 10:12 history edited Another User CC BY-SA 4.0
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Apr 14, 2021 at 10:11 history edited Urb CC BY-SA 4.0
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Apr 14, 2021 at 10:07 history asked Another User CC BY-SA 4.0