Skip to main content
Physics

Return to Answer

used mathjax
Source Link
Urb
Urb
  • 2.7k
  • 4
  • 14
  • 26

$V=-PE cos \theta$$V=-PE \cos \theta$. From this expression, we can deduce that the potential energy is dependent on the angle of orientation, which varies between $-pE$ when the dipole is aligned with the field and $pE$ when the dipole is aligned against the field. Because the energy is least when the field and the dipole are parallel to each other, it follows that this is the most favored orientation. i.e. the dipole tends to align itself with the field.

$V=-PE cos \theta$. From this expression, we can deduce that the potential energy is dependent on the angle of orientation, which varies between $-pE$ when the dipole is aligned with the field and $pE$ when the dipole is aligned against the field. Because the energy is least when the field and the dipole are parallel to each other, it follows that this is the most favored orientation. i.e. the dipole tends to align itself with the field.

$V=-PE \cos \theta$. From this expression, we can deduce that the potential energy is dependent on the angle of orientation, which varies between $-pE$ when the dipole is aligned with the field and $pE$ when the dipole is aligned against the field. Because the energy is least when the field and the dipole are parallel to each other, it follows that this is the most favored orientation. i.e. the dipole tends to align itself with the field.

used mathjax
Source Link
edit approved Apr 3, 2021 at 7:49
Aseem Mittal
edit approved Apr 3, 2021 at 7:49
Aseem Mittal
  • 102
  • 8

V=-PE cos theta$V=-PE cos \theta$. From this expression, we can deduce that the potential energy is dependent on the angle of orientation, which varies between -pE$-pE$ when the dipole is aligned with the field and pE$pE$ when the dipole is aligned against the field. Because the energy is least when the field and the dipole are parallel to each other, it follows that this is the most favored orientation. i.e. the dipole tends to align itself with the field.

V=-PE cos theta. From this expression, we can deduce that the potential energy is dependent on the angle of orientation, which varies between -pE when the dipole is aligned with the field and pE when the dipole is aligned against the field. Because the energy is least when the field and the dipole are parallel to each other, it follows that this is the most favored orientation. i.e. the dipole tends to align itself with the field.

$V=-PE cos \theta$. From this expression, we can deduce that the potential energy is dependent on the angle of orientation, which varies between $-pE$ when the dipole is aligned with the field and $pE$ when the dipole is aligned against the field. Because the energy is least when the field and the dipole are parallel to each other, it follows that this is the most favored orientation. i.e. the dipole tends to align itself with the field.

Source Link
Weak student
Weak student
  • 1

V=-PE cos theta. From this expression, we can deduce that the potential energy is dependent on the angle of orientation, which varies between -pE when the dipole is aligned with the field and pE when the dipole is aligned against the field. Because the energy is least when the field and the dipole are parallel to each other, it follows that this is the most favored orientation. i.e. the dipole tends to align itself with the field.