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Apr 4, 2021 at 19:53 history edited kbakshi314 CC BY-SA 4.0
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Apr 4, 2021 at 19:49 comment added kbakshi314 The answer above alludes to the proof by contradiction by indicating that the shifting of the $\cos\theta$ factor is what enables consistency in the mathematics of the related principles of geometry $-$ Newton's laws $-$ conservation of energy. In the comments above, we observe that an erroneous geometric, and thus kinematic, relationship between the velocities of the masses and rope lead to a contradiction to the Newton's second law of motion. The only case in which this contradiction is resolved is in the case that $v':=u=\frac{v}{\cos\theta}$.
Apr 4, 2021 at 19:43 comment added kbakshi314 @UV0 the idea in the explanation above is proof by contradiction. If we assume, for instance, the wrong kinematic $v'\cos\theta=v$ (instead of the accurate kinematic) and apply the law of conservation of mechanical energy to the point mass system and the $\text{pint mass}\cup\text{rope and pulleys}$ respectively, we obtain $F'=mg$ and $2Fv-mgv'=2Fv-mgv\cos\theta=0$ so that $F=\frac{mg}{2}\cos\theta$ which implies that $F'=2F\cdot\frac{1}{\cos\theta}$. The final expression obtained contradicts Newton's second law $F'=2F\cos\theta$. Therefore the assumption $v'\cos\theta=v$ is incorrect. (2/2)
Apr 4, 2021 at 19:36 history edited kbakshi314 CC BY-SA 4.0
edited text for better explanation
Apr 4, 2021 at 19:31 history edited kbakshi314 CC BY-SA 4.0
edited text for better explanation
Apr 4, 2021 at 19:19 history edited kbakshi314 CC BY-SA 4.0
edited text for better explanation
Apr 4, 2021 at 19:12 comment added kbakshi314 @UV0 let us assume that in both situations the mass moves at constant velocity. Denoting $v':=u$ for clarity, the relationships $v'=u=\frac{v}{cos\theta}$ is derived by geometry (and then kinematics) and $F'=2F\cos\theta$ derived from Newton's laws are true in both situations depicted in the pictures in the OP. We observe that the factor $\cos\theta$ has flipped sides or gets applied to the tension in the rope in one equation and the velocity of the mass in the other. (1/2)
Apr 3, 2021 at 14:16 comment added UV0 I still dont get it,
Mar 29, 2021 at 14:39 history answered kbakshi314 CC BY-SA 4.0