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Nov 1, 2021 at 22:17 comment added Lightcone There is a neat way to deal with this kind of problem: the action variable. In the phase space $(x,p)$, the particle orbits around a closed trajectory $p^2/2m + A|x|^n = E$ clockwise and encloses an area $J \propto \sqrt{2mE}\cdot (E/A)^{1/n} \propto E^{1/2+1/n}$. Then the formula $\tau = \partial J/\partial E$ implies that $\tau \propto E^{1/n-1/2}$. Finding the precise expression for the proportional constant is an easy exercise. Tried to explain more details by posting as an answer, but failed since it is closed. You may refer to: physics.stackexchange.com/a/389454/100521
Mar 18, 2021 at 19:27 history closed G. Smith
ZeroTheHero
Jon Custer
Buzz
Chemomechanics
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Mar 18, 2021 at 18:43 vote accept Adán González
Mar 18, 2021 at 17:57 answer added Eli timeline score: 2
Mar 17, 2021 at 18:16 review Close votes
Mar 18, 2021 at 19:27
Mar 17, 2021 at 17:25 answer added ytlu timeline score: 5
Mar 17, 2021 at 17:07 history edited Adán González CC BY-SA 4.0
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Mar 17, 2021 at 17:06 comment added Adán González @ytlu I made the assumption that $ x'(0) = 0 $
Mar 17, 2021 at 17:05 comment added ytlu The Lplace transform of derivative shoudl involve the intital conditions, the intial position and intial velocity.
Mar 17, 2021 at 17:04 comment added Andrew Steane ... or (same idea another way) start at $x = 0$ with non-zero velocity, and find out how long it takes for the velocity to reach zero.
Mar 17, 2021 at 17:02 comment added Andrew Steane Just an idea: from energy considerations one can deduce that the particle will oscillate, but not in a simple harmonic fashion. So to get the period one way is to take an initial condition of at rest at some $x > 0$, and then don't solve for the whole trajectory, but just aim to find out how long it takes to reach the location $x=0$. That will be one quarter of the period.
Mar 17, 2021 at 16:58 history edited Adán González CC BY-SA 4.0
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Mar 17, 2021 at 16:51 history edited Adán González CC BY-SA 4.0
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Mar 17, 2021 at 16:43 history asked Adán González CC BY-SA 4.0