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Isn't the work done on system of block anda spring-mass system zero, so that there shouldis be no change in potential energy?

So far what I had understood about potential energy is that it is defined for a Systemsystem of particles (With atat least two particles) with forces acting towardsacted by the particles on each other of same magnitude and opposite in direction as, $$-W_\mathrm{conservative} = ΔU.$$

For exampleinstance in case of gravitational potential energy  ,we we only consider work done on small body as there is negligible work done on the earth.

  But in casecases such as : The left side ofthe following example, the concept is not completely clear. Consider a massless spring, the left side of which is attached to the wall, and there is a block attached to the right side of the spring.

  If we consider the block +$\cup$ spring as our system, then the the net work done by internal forces would be zero ,. So what is increasing the potential energy of the system then as we stretch the spring?

I referAs per one of the answers to this question - Questionthis

According to some answer question, I thought Iit seems we need to consider the earth also intoto be a part of the system and Springthe spring just stores potential energy likesimilar to the gravitational field while not really being the part of the system.

Is this reasoning correct? If not, please help me clear these doubtsclarify the concept.

Isn't the work done on system of block and spring zero, so there should be no change in potential energy?

So far what I had understood about potential energy is that it is defined for a System (With at least two particles) with forces acting towards each other of same magnitude and , $$-W_\mathrm{conservative} = ΔU.$$

For example in case of gravitational potential energy  ,we only consider work done on small body as there is negligible work done on the earth.

  But in case such as : The left side of a massless spring is attached to the wall, and there is a block attached to the right side of the spring.

  If we consider block + spring as our system then the the net work done by internal forces would be zero , So what is increasing the potential energy of the system then ?

I refer to this question - Question

According to some answer , I thought I need to consider the earth also into system and Spring just stores potential energy like gravitational field not really being the part of the system.

Is this reasoning correct? If not please help me clear these doubts.

Isn't the work done on a spring-mass system zero, so that there is be no change in potential energy?

So far what I had understood about potential energy is that it is defined for a system of particles (at least two particles) with forces acted by the particles on each other of same magnitude and opposite in direction as, $$-W_\mathrm{conservative} = ΔU.$$

For instance in case of gravitational potential energy, we only consider work done on small body as there is negligible work done on the earth. But in cases such as the following example, the concept is not completely clear. Consider a massless spring, the left side of which is attached to the wall, and there is a block attached to the right side of the spring. If we consider the block $\cup$ spring as our system, then the the net work done by internal forces would be zero. So what is increasing the potential energy of the system as we stretch the spring?

As per one of the answers to this question, it seems we need to consider the earth to be a part of the system and the spring just stores potential energy similar to the gravitational field while not really being the part of the system.

Is this reasoning correct? If not, please help me clarify the concept.

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Isn't the work done on system of block and spring zero  , so there should be no change in potential energy?

So far what I had understood about potential energy is that it is defined for a System  (With altleastat least two particles) with forces acting towards each other of same magnitude and , $$-W_\mathrm{conservative} = ΔU$$$$-W_\mathrm{conservative} = ΔU.$$

For example in case of gravitational potential energy ,we only consider work done on small body as there is negligible work done on the earth.

But in case such as : The left side of a massless spring is attached to the wall, and there is a block attached to the right side of the spring.

If we consider block + spring as our system then the the net work done by internal forces would be zero , So what is increasing the potential energy of the system then ?

I refer to this question - QuestionQuestion

According to some answer , I thought I need to consider the earth also into system and Spring just stores potential energy like gravitational field not really being the part of the system.

Is this reasoning correct  ? If not please help me clear these doubts.

Thanks in Advance ;)

Isn't the work done on system of block and spring zero  , so there should be no change in potential energy?

So far what I had understood about potential energy is that it is defined for a System(With altleast two particles) with forces acting towards each other of same magnitude and , $$-W_\mathrm{conservative} = ΔU$$

For example in case of gravitational potential energy ,we only consider work done on small body as there is negligible work done on the earth.

But in case such as : The left side of a massless spring is attached to the wall, and there is a block attached to the right side of the spring.

If we consider block + spring as our system then the the net work done by internal forces would be zero , So what is increasing the potential energy of the system then ?

I refer to this question - Question

According to some answer , I thought I need to consider the earth also into system and Spring just stores potential energy like gravitational field not really being the part of the system.

Is this reasoning correct  ? If not please help me clear these doubts.

Thanks in Advance ;)

Isn't the work done on system of block and spring zero, so there should be no change in potential energy?

So far what I had understood about potential energy is that it is defined for a System  (With at least two particles) with forces acting towards each other of same magnitude and , $$-W_\mathrm{conservative} = ΔU.$$

For example in case of gravitational potential energy ,we only consider work done on small body as there is negligible work done on the earth.

But in case such as : The left side of a massless spring is attached to the wall, and there is a block attached to the right side of the spring.

If we consider block + spring as our system then the the net work done by internal forces would be zero , So what is increasing the potential energy of the system then ?

I refer to this question - Question

According to some answer , I thought I need to consider the earth also into system and Spring just stores potential energy like gravitational field not really being the part of the system.

Is this reasoning correct? If not please help me clear these doubts.

Source Link

Isn't the work done on system of block and spring zero , so there should be no change in potential energy?

So far what I had understood about potential energy is that it is defined for a System(With altleast two particles) with forces acting towards each other of same magnitude and , $$-W_\mathrm{conservative} = ΔU$$

For example in case of gravitational potential energy ,we only consider work done on small body as there is negligible work done on the earth.

But in case such as : The left side of a massless spring is attached to the wall, and there is a block attached to the right side of the spring.

If we consider block + spring as our system then the the net work done by internal forces would be zero , So what is increasing the potential energy of the system then ?

I refer to this question - Question

According to some answer , I thought I need to consider the earth also into system and Spring just stores potential energy like gravitational field not really being the part of the system.

Is this reasoning correct ? If not please help me clear these doubts.

Thanks in Advance ;)