Timeline for Relativistic Doppler effect derivation
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| S Jul 20, 2016 at 13:11 | history | suggested | Ruggero Turra | CC BY-SA 3.0 |
fix t->tau
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| Jul 20, 2016 at 13:06 | review | Suggested edits | |||
| S Jul 20, 2016 at 13:11 | |||||
| Apr 24, 2013 at 11:58 | vote | accept | Comp_Warrior | ||
| Apr 24, 2013 at 5:54 | comment | added | John Rennie | It's true that I've calculated the doppler shift for the observer in the same place as the emitting object at time 0. For an observer in a different place use two transformations, first the Lorentz transformation into the observers frame, then a second linear transformation in the observers frame to calculate what happens at a different position in that frame. This second transformation is trivial as it's just a translation within the frame and it can't change the observed frequency. | |
| Apr 23, 2013 at 21:47 | comment | added | Comp_Warrior | Very clear and understandable! However one thing that worries me is that you say the observer is at the origin. Suppose you define a frame where the observer is not at the origin (but still at rest) - will the Doppler factor change then? The answer is no of course, but I'm not sure if this is explicit in this derivation. | |
| Apr 23, 2013 at 16:22 | history | answered | John Rennie | CC BY-SA 3.0 |