Timeline for Is there any example where electric and magnetic fields are not perpendicular?
Current License: CC BY-SA 3.0
23 events
| when toggle format | what | by | license | comment | |
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| Mar 2, 2023 at 4:55 | answer | added | user360682 | timeline score: -2 | |
| Aug 3, 2017 at 20:39 | comment | added | MsTais | Only in percent of sources (currents or charges). In free space - never | |
| Jul 26, 2016 at 13:24 | answer | added | Sergei Gorbikov | timeline score: 9 | |
| S Feb 12, 2015 at 17:16 | history | suggested | Timaeus |
I added some tags
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| Feb 12, 2015 at 16:39 | review | Suggested edits | |||
| S Feb 12, 2015 at 17:16 | |||||
| Sep 15, 2014 at 17:57 | answer | added | hariom saranam | timeline score: 0 | |
| Aug 22, 2013 at 13:40 | comment | added | user4552 | @MurodAbdukhakimov: Oops, sorry, you're right. | |
| Aug 22, 2013 at 13:11 | comment | added | Murod Abdukhakimov | @BenCrowell Quote from page cited by you: "if $E\cdot B$ is non-zero there exists an inertial frame in which electric and magnetic fields are proportional." "Proportional" means "Parallel". | |
| Aug 19, 2013 at 13:26 | answer | added | Thanos | timeline score: 13 | |
| Aug 19, 2013 at 13:25 | comment | added | Thanos | @BenCrowell: You really think so? I'll just post it. Thank's! | |
| Aug 18, 2013 at 16:31 | comment | added | user4552 | @Optionparty: You don't seem to be distinguishing between the concepts of electric charge and electric field. You might want to see if you can formulate a separate question that would help you to clatify your understanding of that issue. | |
| Aug 17, 2013 at 18:32 | comment | added | user4552 | @Thanos: I think that should be an answer. | |
| Aug 17, 2013 at 18:29 | comment | added | user4552 | @MurodAbdukhakimov: if ... fields are not perpendicular, then there always exist a reference frame where E is parallel to B Not true. The quantity $E\cdot B$ is a relativistic invariant. See en.wikipedia.org/wiki/… | |
| Aug 17, 2013 at 18:27 | comment | added | user4552 | @Optionparty: A moving electric field, creates the perpendicular magnetic field. No. A changing (not "moving") electric field creates a magnetic field, which may or may not be perpendicular to it. In SciFi's Alien space ships were powered by crossing magnetic fields. Discussion of fictional physics is off-topic for this site. | |
| Aug 17, 2013 at 17:54 | answer | added | bobot | timeline score: -3 | |
| Apr 18, 2013 at 14:54 | comment | added | Murod Abdukhakimov | please note that if $\vec{E} \vec{B}$ is not equal to $0$, i.e. fields are not perpendicular, then there always exist a reference frame where $\vec{E}$ is parallel to $\vec{B}$. In particular, this is the case of neutrino field. | |
| Apr 18, 2013 at 12:44 | comment | added | Michael | Just put a charge at rest in a magnetic field. The Coulomb field goes out in all directions, and will cross the magnetic field at every possible angle. Nothing special happens. | |
| Apr 18, 2013 at 12:33 | comment | added | Thanos | @KaziarafatAhmed: Yes there is! In wave guides there modes of propagation. What we know as transverse electromagnetic field is just the TEM mode of a field. There are also the TE(transverse electric mode) with $B_z\neq 0$ and the TM(transverse Magnetic mode) with $E_Z\neq 0$ where $z$ is the direction of propagation! | |
| Apr 18, 2013 at 12:27 | history | edited | Waffle's Crazy Peanut |
edited tags
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| Apr 15, 2013 at 15:31 | comment | added | Self-Made Man | Is there anything amphibian between electric and magnetic field? @Optionparty | |
| Apr 14, 2013 at 19:36 | comment | added | Optionparty | A moving electric field, creates the perpendicular magnetic field. | |
| Apr 14, 2013 at 17:18 | comment | added | seb | You may want to read up on Maxwell's equations that describe electromagnetic waves. That E (electric-field) is perpendicular to B (magnetic-field) is just the case in vacuum. It does not have to be true otherwise. | |
| Apr 14, 2013 at 15:06 | history | asked | Self-Made Man | CC BY-SA 3.0 |