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Jan 13, 2021 at 15:27 comment added ProfRob @Clone, probably because it isn't drawn accurately enough. In the end it is just a conceptual device, the reason it doesn't turn is that both $\nabla \times \vec{B} = 0$, which by Stokes theorem means that $\oint \vec{B}\cdot d\vec{l}=0$.
Jan 13, 2021 at 14:45 comment added Clone Okay, I figured it out. The net force is zero on the paddle, I suppose. Thanks for the answer.
Jan 13, 2021 at 14:39 comment added Clone Thank you for the reply! That is exactly my problem, I dont understand why the paddle wheel does not rotate if I put it outside of the conductor. Thank you for the link to the other answer, what I didnt understand from that was why the paddle does not rotate even though the arrow on the bottom is the "biggest". The field is stronger closer to the wire so I would expect that the paddle would rotate clockwise.
Jan 13, 2021 at 14:36 history answered ProfRob CC BY-SA 4.0