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Jan 9, 2021 at 2:06 history closed Jon Custer
Michael Seifert
Brian
Yashas
joseph h
Duplicate of Question about normal force acting on a mass on an inclined plane
Jan 8, 2021 at 10:19 comment added Yashas There is no acceleration along the direction perpendicular to the inclined plane. This is why you equate $N$ to $mg \cos \theta$. There is acceleration along the x and y direction. Therefore, equating $N \cos \theta$ to $mg$ is wrong.
S Jan 7, 2021 at 11:22 history edited engineer CC BY-SA 4.0
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S Jan 7, 2021 at 11:22 history suggested user256872 CC BY-SA 4.0
math equations.
Jan 7, 2021 at 9:11 review Suggested edits
S Jan 7, 2021 at 11:22
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Jan 9, 2021 at 2:06
Jan 7, 2021 at 8:40 vote accept SJY
Jan 7, 2021 at 8:39 history edited SJY CC BY-SA 4.0
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Jan 7, 2021 at 8:22 comment added Danny LeBeau Does this answer your question? Question about normal force acting on a mass on an inclined plane
Jan 7, 2021 at 8:21 answer added Farcher timeline score: 0
Jan 7, 2021 at 8:15 answer added user256872 timeline score: 3
Jan 7, 2021 at 7:56 review First posts
Jan 7, 2021 at 10:47
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Jan 7, 2021 at 7:51 history asked SJY CC BY-SA 4.0