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Dec 4 at 19:33 history edited Gold CC BY-SA 4.0
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Dec 4 at 15:10 comment added Chandra Prakash Is it safe assumption to make that since $a_p|0\rangle\ne0$, the vacuum is not an eigenstate of number operator $a_p^{\dagger}a_p$?
Jan 6, 2021 at 17:34 history edited Gold CC BY-SA 4.0
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Jan 6, 2021 at 17:16 vote accept AlmostClueless
Jan 5, 2021 at 22:50 history edited Gold CC BY-SA 4.0
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Jan 5, 2021 at 22:24 history answered Gold CC BY-SA 4.0