Skip to main content
5 events
when toggle format what by license comment
Jan 5, 2021 at 12:40 vote accept miniplanck
Jan 3, 2021 at 15:46 answer added miniplanck timeline score: 1
Jan 3, 2021 at 13:14 comment added miniplanck @user110971 So $<\alpha(t)>$ is basically a function AND a convolution at the same time. Applying the fourier tranform, one gets $F(\alpha) = F(K(t)) \cdot F(F(t)) \Leftrightarrow <\alpha (\omega)> = \bar{\chi}(\omega) \cdot \tilde{F}(\omega)$ which is our final answer. Am I right?
Jan 3, 2021 at 12:29 comment added user110971 Hint: convolution theorem.
Jan 3, 2021 at 12:13 history asked miniplanck CC BY-SA 4.0